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vesna_86 [32]
3 years ago
14

The total length of wires a b and c is 445 cm wire a is 45 cm longer then wire b and wire b is half as long as wire c how long i

s wire a
Mathematics
1 answer:
Oksana_A [137]3 years ago
6 0

Answer:

a = 145\ cm

Step-by-step explanation:

Given

a + b + c = 445

a = 45 + b

b = \frac{1}{2}c

Required

Determine the length of a

Solve for c in b = \frac{1}{2}c

2 * b = \frac{1}{2}c * 2

2b  = c

c = 2b

Substitute c = 2b and a = 45 + b in a + b + c = 445

a + b + c = 445

45 + b + b + 2b = 445

45 + 4b = 445

Solve for 4b

4b = 445 - 45

4b = 400

Solve for b

b = 400/4

b = 100

Recall that: a = 45 + b

a=45+100

a = 145\ cm

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6 0
3 years ago
The perimeter of a triangle is 12in. After a dilation, the perimeter is now 60in. What is the scale factor?
LenaWriter [7]

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6 0
3 years ago
Read 2 more answers
Michelle has a jar of quarters and dimes totalling to 3.10 if there are sixteen coins in the jar how many more quarters are ther
Sav [38]
Q + d = 16....q = 16 - d
0.25q + 0.10d = 3.10

0.25(16 - d) + 0.10d = 3.10
4 - 0.25d + 0.10d = 3.10
-0.25d + 0.10d = 3.10 - 4
-0.15d = -0.90
d = -0.90/-0.15
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5 0
3 years ago
University Theater sold 465 tickets for a play. Tickets cost $23 per adult and $13 per senior citizen. If total receipts were $7
liq [111]

<u>Answer:</u>

355 senior citizen tickets were sold.

<u>Step-by-step explanation:</u>

Assuming a to the the ticket of adults and s to be the ticket of senior citizens, we can write two equations as:

a +s=465 --- (1)

23a+13s=7145 --- (2)

From equation 1, a=465-s.

Substitute a in equation 2 to get:

23 (465-s) + 13s = 7145

10695 - 23s +13s =7145

-10s = -3550

s = 355

Therefore, there were 355 senior citizen tickets sold.

8 0
3 years ago
A 4-kilogram bag of birdseed costs $12.69. What is the unit price, rounded to the
igomit [66]

Answer:

$3.17

Step-by-step explanation:

Take the $12.69 and divide it by the 4 kilograms and you get 3.17. (This is rounded)

3 0
3 years ago
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