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vesna_86 [32]
3 years ago
14

The total length of wires a b and c is 445 cm wire a is 45 cm longer then wire b and wire b is half as long as wire c how long i

s wire a
Mathematics
1 answer:
Oksana_A [137]3 years ago
6 0

Answer:

a = 145\ cm

Step-by-step explanation:

Given

a + b + c = 445

a = 45 + b

b = \frac{1}{2}c

Required

Determine the length of a

Solve for c in b = \frac{1}{2}c

2 * b = \frac{1}{2}c * 2

2b  = c

c = 2b

Substitute c = 2b and a = 45 + b in a + b + c = 445

a + b + c = 445

45 + b + b + 2b = 445

45 + 4b = 445

Solve for 4b

4b = 445 - 45

4b = 400

Solve for b

b = 400/4

b = 100

Recall that: a = 45 + b

a=45+100

a = 145\ cm

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Help me class8 (surds)​
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Answer:

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Step-by-step explanation:

For a start simplify each of the roots:

  • \sqrt{72} =\sqrt{36*2} =6\sqrt{2}
  • \sqrt{50} =\sqrt{25*2} =5\sqrt{2}
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Now simplify the expression in steps:

\sqrt{72}-\cfrac{48}{\sqrt{50} }  -\cfrac{45}{\sqrt{128} }  +2\sqrt{98} =

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20\sqrt{2}-\cfrac{609}{40\sqrt{2} } =

20\sqrt{2}-\cfrac{609*\sqrt{2} }{40\sqrt{2} *\sqrt{2} } =

20\sqrt{2}-\cfrac{609\sqrt{2} }{40*2 } =

20\sqrt{2}-\cfrac{609\sqrt{2} }{80 } =

\sqrt{2} (20-7\cfrac{49}{80} )=

\sqrt{2} *12\cfrac{31}{80} =

\cfrac{991\sqrt{2} }{80}

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