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3 years ago

Find the measure of the smallest angle?

Mathematics

1 answer:

weeeeeb [17]3 years ago

6 0

Answer:

m ∠RMK = 51°

Step-by-step explanation:

m ∠JMK = m ∠RMK + m ∠JMR

10x + 19 = 7x - 26 + 6x + 12

10x +19 = 13x -14

19 = 3x -14

33 = 3x

11 = x

m ∠RMK = 7(11) - 26 = 51°

m ∠JMR = 6 (11) + 12 = 78

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The mean of Alice's last 5 math test scores is 88. The first 4 of these 5 math test scores were 87, 75, 93, and 85. What score d

stiks02 [169]

Answer:

Step-by-step explanation:

x is the score she got on the fifth test.

Since her average score is 88, the sum of all five tests is 5×88.

x + 87 + 75 + 93 + 85 = 5×88 = 440

x = 440 - 87 - 75 - 93 - 85

x = 100

She got a 100 on her fifth test.

6 0

3 years ago

18 = 3 (3x - 6) help please!

Lady_Fox [76]

Answer: 4

Step-by-step explanation:

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3 years ago

Each wheel on a car has a diameter of 22 inches.

ch4aika [34]

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3 0

3 years ago

Plz help Events A and B are independent. Let event A be the event that a person chooses and buys a certain pear from the grocery

kompoz [17]

Hi all

Answer:

I had this question on my MAP testing just today, and I answered with

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7 0

3 years ago

Complete the square to rewrite y-x^2-6x+14 in vertex form. then state whether the vertex is a maximum or minimum and give its co

ycow [4]

Answer:

$y= x^2 -6x +(\frac{6}{2})^2 +14 -(\frac{6}{2})^2$

And solving we have:

$y= x^2 -6x +9 + 14 -9$

$y= (x-3)^2 +5$

And we can write the expression like this:

$y-5 = (x-3)^2$

The vertex for this case would be:

$V= (3,5)$

And the minimum for the function would be 3 and there is no maximum value for the function

Step-by-step explanation:

For this case we have the following equation given:

$y= x^2 -6x +14$

We can complete the square like this:

$y= x^2 -6x +(\frac{6}{2})^2 +14 -(\frac{6}{2})^2$

And solving we have:

$y= x^2 -6x +9 + 14 -9$

$y= (x-3)^2 +5$

And we can write the expression like this:

$y-5 = (x-3)^2$

The vertex for this case would be:

$V= (3,5)$

And the minimum for the function would be 3 and there is no maximum value for the function

4 0

4 years ago