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valina [46]
1 year ago
15

Need helppp asappp!!

Mathematics
2 answers:
Rom4ik [11]1 year ago
8 0

Answer:

1/2

Step-by-step explanation:

a common ratio is a ratio that is found in any of those numbers listed, in othere words it's a common factor in those numbers

jenyasd209 [6]1 year ago
8 0

Answer:

1/2

Step-by-step explanation:

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Manuel made 5 identical necklaces, each having beads and a pendant. The total cost of the beads and pendants for all 5 necklaces
valentinak56 [21]

Answer:

2.3

Step-by-step explanation:

Step 1: Divide 30.50 by 5 to get that each necklaces costs 6.1.

Step 2: Subtract 6.1 (cost for 1 necklace) and 3.80 (price of beads)

Your answer is 2.3! Please mark this as brainliest

4 0
3 years ago
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Is the square root of 5+1/5 rational or irrational
Vikentia [17]
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3 years ago
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3 years ago
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Keith_Richards [23]

Answer:

1

Step-by-step explanation:

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4 0
3 years ago
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Suppose that three numbers are selected one by one, at random, and without replacement, from the set of integers {1, 2, 3, . . .
fiasKO [112]

A - the third number falls between the first two

B - the first number is smaller than the second

P(A|B)=\dfrac{P(A\cap B)}{P(B)}\\\\ |\Omega|=n(n-1)(n-2)\\\\ |B|=\dfrac{n!}{2}\\\\ |A\cap B|=\dfrac{\dfrac{n!}{2}}{3}=\dfrac{n!}{6}\\\\ P(A\cap B)=\dfrac{\dfrac{n!}{6}}{n(n-1)(n-2)}=\dfrac{n!}{6n(n-1)(n-2)}=\dfrac{(n-3)!}{6}\\ P(B)=\dfrac{\dfrac{n!}{2}}{n(n-1)(n-2)}=\dfrac{n!}{2n(n-1)(n-2)}=\dfrac{(n-3)!}{2}\\\\ P(A|B)=\dfrac{\dfrac{(n-3)!}{6}}{\dfrac{(n-3)!}{2}}\\\\ P(A|B)=\dfrac{(n-3)!}{6}\cdot\dfrac{2}{(n-3)!}=\dfrac{1}{6}=\dfrac{1}{3}

3 0
3 years ago
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