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Brums [2.3K]
3 years ago
5

ASAP PLEASE ERROR ANALYSIS combining like terms?

Mathematics
1 answer:
nirvana33 [79]3 years ago
6 0
13x + 5 + 17x - 4.5 + x
21x + 0.5
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Determine whether f(x) = –5x^2 – 10x + 6 has a maximum or a minimum value. Find that value and explain how you know.
polet [3.4K]

Answer:

The vertex is the point (-1,11). is a maximum

Step-by-step explanation:

we know that

The equation of a vertical parabola in vertex form is equal to

f(x)=a(x-h)^{2}+k

where

(h,k) is the vertex

a is a coefficient

if a > 0 the parabola open upward and the vertex is a minimum

if a < 0 the parabola open downward and the vertex is a maximum

we have

f(x)=-5x^{2}-10x+6

Convert to vertex form

Complete the square

f(x)-6=-5x^{2}-10x

Factor the leading coefficient

f(x)-6=-5(x^{2}+2x)

f(x)-6-5=-5(x^{2}+2x+1)

f(x)-11=-5(x^{2}+2x+1)

Rewrite as perfect squares

f(x)-11=-5(x+1)^{2}

f(x)=-5(x+1)^{2}+11

The vertex is the point (-1,11)

The coefficient a=-5

so

a < 0 the parabola open downward and the vertex is a maximum

5 0
4 years ago
out of 45 times at bat, Raul got 19 hits find Ralph's batting average rounded to the nearest thousandth
Aleksandr-060686 [28]
Batting average = hits/total = 19/45 = 0.422
7 0
3 years ago
Apply the distributive property to simplify the expression. −9(−2x − 3)
torisob [31]

Answer:

Step-by-step explanation:

you do -9 times -2x which is 9x2X

then you do -9 times -3

so your answer is 9times2x-29

7 0
4 years ago
What the 2 soultion answer to <br> y = 6x − 4<br> y = 5x − 3
d1i1m1o1n [39]

y= 6x -4~~~~~~...(i)\\\\y = 5x -3~~~~~~...(ii)\\\\\text{From (i) and (ii):}\\\\~~~~~6x -4 = 5x -3\\\\\implies 6x -5x = -3 + 4\\\\\implies x = 1\\\\\text{Substitute x = 1 in equation (i):}\\\\y = 6(1) -4 = 2\\\\\text{Hence,}~ (x,y) = (1,2)

6 0
2 years ago
Hurry please help me!
Dennis_Churaev [7]

Answer:

  • d. 23

Step-by-step explanation:

Let the number of cars be x and buses be y

<u>Then we have below inequalities as per given:</u>

  • 5x + 32y ≤ 1310
  • x + y ≤ 135

It is easy to notice that cars occupy 6 times less area than buses but cost of parking is 3 times less. So we would need maximum number of cars and minimum number of buses to maximize income

<u>Let's assume there are 135 cars and buses, then from the second inequality:</u>

  • x = 135 - y

<u>Substitute it in the first one:</u>

  • 5(135 - y) + 32y ≤ 1310
  • 675 - 5y + 32y ≤ 1310
  • 27y ≤ 1310 - 675
  • 27y ≤ 635
  • y ≤ 635/27
  • y≤ 23.5

The greatest number of buses is 23

Option D. 23 is correct

5 0
4 years ago
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