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sleet_krkn [62]
2 years ago
13

F(x)=x^2+5x-1 is shifted 3 units left. the result is g(x). what is g(x)

Mathematics
1 answer:
frez [133]2 years ago
6 0

\rm F(x)=x^2+5x-1, is shifted 3 units left. the result is g(x) is,\rm y=(x+3)^2+5(x+3)-1

<h3>What exactly is a function?</h3>

A function is a statement, rule, or law that specifies the connection between two variables.

Functions are common in mathematics and are required for the formulation of physical connections.

The given function is;

\rm F(x)=x^2+5x-1

The given function is shifted 3 units left. It is can be obtained by drawing the graph for both functions.

The graph for both functions is attached below and shows that function is shifted 3 units left.

Hence, the value of \rm g(x)=(x+3)^2+5(x+3)-1.

To learn more about the function, refer to:

brainly.com/question/5245372

#SPJ1

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Find the midsegment of triangle ABC so that it is parallel to side BC and label it as segment EG on the graph.
Lelechka [254]

Answer:

Coordinate of E:(-2,3) Coordinate of G: (2.5,1.5)

Parallel: slopes both = -1/3

1/2 segment: EG length= 3 BC length=6: This is the only one I'm not sure about.

I will show the work for both the problems down below.

Step-by-step explanation:

Finding coordinates:

1+(-5)/2=-2  5+1/2=3

(-2,3)

1+4/2= 2.5   5+(-2)/2= 1.5

(2.5,1.5)

Show work verifying the EG and BC are parallel:

You can do this by finding the slope

Slop formula (y2-y1)/(x2-x1)

(1.5-3)/(2.5-(-2))

Then simplify

-1.5/2/5= -1/3 which i your slope. You use the same formula and follow thee same steps for the points of BC and both will come up as -1/4 meaning they are parallel.

Show work verifying that EG and BC are parallel:

Use distance formula to find how long each line is

√(x2-x1)^2+(y2-y1)^2

√(2.5-(-2)^2)+(1.5-3)^2

Simplify

√4.5+(1.5)=3

Do the same thing with BC and you will get 6






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Step-by-step explanation:

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The fifth term of the sequence will be 11, -1, 2, 5, 8,
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For this case we have that, by definition, the domain of a function is given by all the values for which the function is defined.

Having said that, we have the following function:

r (x) = \frac {2x} {x-1}

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Thus, the domain of r (x) is given by all real numbers except 1.

Answer:

all real numbers except 1.

Option A

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