<span> If all numbers are greater than zero and no repeated numbers exist these are the 5 possible combinations:
1 + 2 + 8
1 + 3 + 7
1 + 4 + 6
2 + 3 + 6
2 + 4 + 5.
If one number is allowed to be zero and no repeated numbers exist these are 5 combinations:
</span><span> 0 + 11
1 + 1 + 9
2 + 2 + 7
3 + 3 + 5
4 + 4 + 3
5 + 5 + 1
</span><span>
Hope this helps
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All it takes for a relation to be a function is for each possible first number of a pair there's only one possible second number.
So if any of the sets has two pairs with the same first number, that one's not a function.
The last one has (3,2) and (3,5) so isn't a function.
Answer:
x = (R -C)/A
Step-by-step explanation:
The variable X is multiplied by A and the product has C added. Undo these operations in reverse order: subtract C, then divide by A. Of course all operations are done to both sides of the equation.
AX +C = R
AX = R -C . . . . . .subtract C
X = (R -C)/A . . . . divide by A
