Didn't answer all because I got lazy and I think you should try and do the rest yourself. Did this in 5 mins, try putting more effort into your homework. This is basic mathematics.
Find the squares of (y+3)
1 answer:
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Answer:
Measures are SV=9 units., SY=14 units, YW= , YW=
Step-by-step explanation:
Given Y is the circumcenter of ΔSTU. we have to find the measures SV, SY, YW and YX.
As Circumcenter is equidistant from the vertices of triangle and also The circumcenter is the point at which the three perpendicular bisectors of the sides of the triangle meet.
Hence, VY, YW and YX are the perpendicular bisectors on the sides ST, TU and SU.
Given ST=18 units.
As VY is perpendicular bisector implies SV=9 units.
Also in triangle VTY
⇒
⇒ VY^{2}=115
As vertices of triangle are equidistant from the circumcenter
⇒ SY=YT=UY=14 units
Hence, SY is 14 units
In ΔUWY,
⇒
⇒ ⇒ YW=
In ΔYXU,
⇒
⇒ ⇒ YW=
Hence, measures are SV=9 units., SY=14 units, YW= , YW=