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MArishka [77]
2 years ago
13

Not sure how to do this

Mathematics
2 answers:
ololo11 [35]2 years ago
4 0
It should be this answer i got it off the internet it should be right

netineya [11]2 years ago
3 0

Answer:

\underline{\boxed{\sf{2(x - 11)(x + 11)}}}

Step-by-step explanation:

\sf{2x^2 - 242}

<u>Common factor :</u>

\sf{2x^2 - 242}

\sf{2(x^2 - 121)}

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

<u>Use the sum-product pattern :</u>

\sf{2(x^2-121)}

\sf{2(x^2 + 11x-11x - 121)}

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

<u>Common factor from the two pairs :</u>

\sf{2(x^2 + 11x-11x - 121)}

\sf{2(x(x+11) -11(x + 11))}

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

<u>Rewrite in factored form :</u>

\sf{2(x(x+11)- 11(x + 11))}

\sf{2(x - 11)(x + 11)}

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

<u>Solution :</u>

\sf{2(x - 11)(x + 11)}

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If I set A=0 to find the roots, the maximum will be at wmax=-b/2a which is exactly 1/2 way between the roots-(3/2)*w^2+600w=0
-b=-600
2a=-3
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w=200
And, since 3w+2l=1200
3*200+2l=1200
2l = 600
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The dimensions of the largest enclosure willbe when width = 200 ft and length = 300 ft
check answer:
3w+2l=1200
3*200+2*300=1200
600+600=1200
1200=1200
and A=w*l
A=200*300
A=60000 ft2
To see if this is max area change  w and l slightly but still make 3w+2l=1200 true, like
w=200.1
l=299.85
A=299.85*200.1
A=59999.985
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