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Masja [62]
3 years ago
8

ine AB passes through points A(–6, 6) and B(12, 3). If the equation of the line is written in slope-intercept form, y = mx + b,

then m = – and b
Mathematics
1 answer:
Alja [10]3 years ago
6 0
Y-6=-1/6(x+6)
y = -1/6x +5

m= -1/6
b=5
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Please could someone help me with these questions sorry about the scribbling on one page I got stuck
Sloan [31]
Question 4
So the polygon has 10 sides, to calculate how much all the interior angles are summed up, you have to see how many triangles you can fit into the polygon (this works for any polygon), in this case it is 8 (see file attached). Therefore you do 8 x 180 = 1440, so the overall angle is 1440º. Now you do 1440 : 10, because there are 10 equal angles, and that is 144º. 
Every angle has 144º

question 5
Bearings are always measured clockwise and you always start north. You are at point A and want to go to point B, how much do you have to turn (clockwise!!)? 
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8 0
3 years ago
Which of the following represent a linear inequality in open-sentence form? (Select all that apply.) 2x - 7y > 10, 3 < 5,
IrinaK [193]

The answer would be 8 + x > 5.

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6 0
3 years ago
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F(-2)=-2²+3(-2)-2 find f(-2)
olga_2 [115]

Answer:

F(-2)=-2²+3(-2)-2=4+-6×-2=4+12=16

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3 years ago
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A cube-shaped box has a volume of 1/8 of a cubic meter. What is the perimeter of each of its
belka [17]

Given:

The volume of a cube-shaped box is \dfrac{1}{8} cubic meter.

To find:

The perimeter of each of its faces.

Solution:

Let "a" be the side length of the cube shaped box. Then the volume of the box is:

V=(side)^3

V=a^3

It is given that the volume of a cube-shaped box is \dfrac{1}{8}  cubic meter.

a^3=\dfrac{1}{8}

Taking cube root on both sides, we get

a=\dfrac{1}{2}

Now, the perimeter of each face of a cube is:

P=4a

Where, a is the side length of the cube.

Putting a=\dfrac{1}{2}, we get

P=4\times \dfrac{1}{2}

P=2

Therefore, the perimeter of each face of a cube-shaped box is 2 meters.

5 0
3 years ago
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