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3 years ago

8

ine AB passes through points A(–6, 6) and B(12, 3). If the equation of the line is written in slope-intercept form, y = mx + b,

then m = – and b

1 answer:

Alja [10]3 years ago

6 0

Y-6=-1/6(x+6)
y = -1/6x +5

m= -1/6
b=5

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For about $1 billion in new space shuttle expenditures, NASA has proposed to install new heat pumps, power heads, heat exchanger

11111nata11111 [884]

Answer:

The probability of one or more catastrophes in:

(1) Two mission is 0.0166.

(2) Five mission is 0.0410.

(3) Ten mission is 0.0803.

(4) Fifty mission is 0.3419.

Step-by-step explanation:

Let <em>X</em> = number of catastrophes in the missions.

The probability of a catastrophe in a mission is, P (X) = $p=\frac{1}{120}$ .

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X </em>is:

$P(X=x)={n\choose x}\frac{1}{120}^{x}(1-\frac{1}{120})^{n-x};\x=0,1,2,3...$

In this case we need to compute the probability of 1 or more than 1 catastrophes in <em>n</em> missions.

Then the value of P (X ≥ 1) is:

P (X ≥ 1) = 1 - P (X < 1)

= 1 - P (X = 0)

$=1-{n\choose 0}\frac{1}{120}^{0}(1-\frac{1}{120})^{n-0}\\=1-(1\times1\times(1-\frac{1}{120})^{n-0})\\=1-(1-\frac{1}{120})^{n-0}$

(1)

Compute the compute the probability of 1 or more than 1 catastrophes in 2 missions as follows:

$P(X\geq 1)=1-(1-\frac{1}{120})^{2-0}=1-0.9834=0.0166$

(2)

Compute the compute the probability of 1 or more than 1 catastrophes in 5 missions as follows:

$P(X\geq 1)=1-(1-\frac{1}{120})^{5-0}=1-0.9590=0.0410$

(3)

Compute the compute the probability of 1 or more than 1 catastrophes in 10 missions as follows:

$P(X\geq 1)=1-(1-\frac{1}{120})^{10-0}=1-0.9197=0.0803$

(4)

Compute the compute the probability of 1 or more than 1 catastrophes in 50 missions as follows:

$P(X\geq 1)=1-(1-\frac{1}{120})^{50-0}=1-0.6581=0.3419$

6 0

3 years ago

A standard card deck has 52 cards consisting of 26 black and 26 red cards. Three cards are dealt from a shuffled deck, without

Alekssandra [29.7K]

Answer:

6 / 51

Step-by-step explanation:

It is false.

Reason:

The probability of picking a black card at first is:

26 / 52 = 1/2

There are now 25 black cards and 51 cards in total.

The probability of picking another black card, if there's no replacement is now:

25 / 51

Now, there are 24 black cards and 50 cards left in total.

The probability of picking a black card without replacement now becomes:

24 / 50 = 12 / 25

Hence, the probability of picking three black cards without replacement is:

1/2 * 25/51 * 12 / 25 = 300 / 2550

In simplest form, it is 6 / 51

7 0

2 years ago

If 2a + 7b+2c=16 and 2a + 3b +2c= 8, then b = ?<br> (A)-2<br> (B) O<br> (C) 2<br> (D) 4<br> (E) 6

Sauron [17]

Answer:

(C) 2

Step-by-step explanation:

Given equations 2a + 7b+2c=16 and 2a + 3b +2c= 8, you want to know the value of b.

<h3>Solution</h3>

The coefficients of 'a' and 'c' are the same in the two equations, so we can eliminate those variables by subtracting one equation from the other. We can keep the resulting coefficient of 'b' positive if we subtract the second equation from the first.

(2a +7b +2c) -(2a +3b +2c) = (16) -(8)

4b = 8 . . . . . . . simplify

b = 2 . . . . . . . divide by 4

5 0

1 year ago

Find the equation using the point-slope formula:<br> (4, 3) m = -3

natita [175]

Answer:

y = 2/3x - 3

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

The path of a race will be drawn on a coordinate grid like the one shown below. The starting point of the race will be at (−5.5,

Mazyrski [523]

A) the starting point is in quadrant Q because the x-value is negative, while the y-value is positive. The finishing point is in quadrant S because the x-value is positive, while the y-value is negative.
B) The points are connected by a straight line, so you don't have to wander off. By the way, the checkpoint is in Quadrant P.

3 0

3 years ago