
×

First, convert

to an improper fraction. Use this rule:

=

/ Your problem should look like:

×
Second, simplify 4 × 6 to 24. / Your problem should look like:

×
Third, simplify 24 + 1 to 25. / Your problem should look like:

×
Fourth, apply this rule:

×

=

/ Your problem should look like:
Fifth, simplify 3 × 25 to 75. / Your problem should look like:
Sixth, simplify 5 × 6 to 30. / Your problem should look like:
Seventh, simplify. / Your problem should look like:
Eighth, convert to mixed fraction. / Your problem should look like:

Answer:
Answer:



Step-by-step explanation:
<u>Optimizing With Derivatives
</u>
The procedure to optimize a function (find its maximum or minimum) consists in
:
- Produce a function which depends on only one variable
- Compute the first derivative and set it equal to 0
- Find the values for the variable, called critical points
- Compute the second derivative
- Evaluate the second derivative in the critical points. If it results positive, the critical point is a minimum, if it's negative, the critical point is a maximum
We know a cylinder has a volume of 4
. The volume of a cylinder is given by

Equating it to 4

Let's solve for h

A cylinder with an open-top has only one circle as the shape of the lid and has a lateral area computed as a rectangle of height h and base equal to the length of a circle. Thus, the total area of the material to make the cylinder is

Replacing the formula of h

Simplifying

We have the function of the area in terms of one variable. Now we compute the first derivative and equal it to zero

Rearranging

Solving for r

![\displaystyle r=\sqrt[3]{\frac{4}{\pi }}\approx 1.084\ feet](https://tex.z-dn.net/?f=%5Cdisplaystyle%20r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B4%7D%7B%5Cpi%20%7D%7D%5Capprox%201.084%5C%20feet)
Computing h

We can see the height and the radius are of the same size. We check if the critical point is a maximum or a minimum by computing the second derivative

We can see it will be always positive regardless of the value of r (assumed positive too), so the critical point is a minimum.
The minimum area is


Answer:
slope = 
Step-by-step explanation:
calculate the slope m using the slope formula
m = 
with (x₁, y₁ ) = (9, 6 ) and (x₂, y₂ ) = (4, 5 )
m =
=
= 
Try A) 60 degrees; 1/2. Your answer was incorrect because cos(60 degrees) is 1/2, cos(30 degrees) is square root 3 /2 not 1 or square root 2 /2