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Anuta_ua [19.1K]
2 years ago
5

What is the standard equation of a parabola with a vertex of (0, 0) and a focus of (-6, 0)?

Mathematics
1 answer:
zhuklara [117]2 years ago
6 0

Step-by-step explanation:

Notice the vertex and focus have the same y coordinate so this means we will have sideways parabola.

Equation of a sideways parabola is

(y - k) {}^{2}  = 4p(x - h)

Since the vertex is (0,0), we can get rid of h and k.

{y}^{2}  = 4px

Next Section: Value of P:

The value of P is the displacement between the focus and vertex.

So we do

p = x _{focus} - x _{vertex}

p =  - 6 - 0

p =  - 6

{y}^{2}  = 4( - 6)x

{y}^{2}  =  - 24x

or

- \frac{ {y}^{2} }{24}  = x

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