I = 400
400=8000*0.02*t
400/(8000*0.02) =t
400/160=t
2.5 = t
2 1/2 years
3/8 of the fertilizer is left for the third garden
A role-playing game uses an 11-sided die that displays the numbers 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 What is the probability tha
kondor19780726 [428]
Using it's concept, it is found that there is a 27.3% probability that someone throws the 11-sided die one time and rolls a number 9 or higher.
<h3>What is a probability?</h3>
A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.
In this problem, there are 11 numbers, 3 of which are 9 or higher, hence the probability is:
p = 3/11 = 0.273 = 27.3%.
More can be learned about probabilities at brainly.com/question/14398287
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1st drop(.71) 2nd drop(-1.22)
It is more than 0, because you cancel the x, and you get 2+5, which is 7
