Question

Find the x- and y-intercepts of the parabola y=x2+10x+4

Answer 1

Answer:

x-intercepts: -5 +/-$\sqrt{21}$. y-intercept: 4

Step-by-step explanation:

For x-intercepts use the quadratic equation

$x= (-b +/-\sqrt{b^2-4ac} )/2a$

Fill in your values:

$x= (-10 +/-\sqrt{100-16} )/2$

And solve

$x=-5 +/- \sqrt{21}$

For y-intercepts set x=0 and solve. In this case, setting x= 0 gives you y=4.