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3 years ago

PLEASE HELP ME ASAP!!! THIS IS DUE TODAY!!!! I need to find y-intercept and slope using (-18,4)&(-7,4)

Mathematics

2 answers:

Lana71 [14]3 years ago

4 0

Answer:

can someone please help me with this

Step-by-step explanation:

Mekhanik [1.2K]3 years ago

3 0

Answer:

y=4

Step-by-step explanation:

I use the slope formula

y2-y1/x2-x1

4-4=0

-18-(-7)=11

Finding the y-intercpt

I use (-7,4). Since you know the slope-intercpet form which is y=mx+b

y=mx+b

4=0(-7)+b

4=0+b ( subtract zero on both sides)

4=b

Thus, the equation of the line is y=4.

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Identify the zeros of the function f(x) = 4x2 − 8x − 1 using the Quadratic Formula. HELP ASAP!!

forsale [732]

$1+\dfrac{\sqrt{5}}{2},1-\dfrac{\sqrt{5}}{2}$

Step-by-step explanation:

The given equation is $4x^{2}-8x-1$

Let $a$ be the coefficient of $x^{2}$

Let $b$ be the coefficient of $x$

Let $c$ be the constant.

Then the roots α,β for the equation $ax^{2}+bx+c$ are $\dfrac{-b+\sqrt{b^{2}-4ac} }{2a},\dfrac{-b-\sqrt{b^{2}-4ac} }{2a}$

So,α= $\frac{-b+\sqrt{b^{2}-4ac} }{2a}=\frac{8+\sqrt{64+16} }{8}=\frac{8+4\sqrt{5}}{8}=1+\frac{\sqrt{5}}{2}$

β= $\frac{-b-\sqrt{b^{2}-4ac} }{2a}=\frac{8-\sqrt{64+16} }{8}=\frac{8-4\sqrt{5}}{8}=1-\frac{\sqrt{5}}{2}$ .

So the roots are $1+\frac{\sqrt{5}}{2},1+\frac{\sqrt{5}}{2}$

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BlackZzzverrR [31]

ANSWER: y=x-8

EXPLANATION:

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prisoha [69]

Hello There!

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