All categories

2 years ago

Graph a triangle ABC and perform a translation of (x + 4, y − 3) to create triangle A′B′C′.

1 answer:

5 0

The new angle A 'B' C will be congruent to angle A,B,C, as it was just moved or shifted lightly 4 times and down 3 times.

<h3>What is the angle about?</h3>

Lets make A B C to be the angles that has coordinate.

A = (0,0)

B = (-3, 0)

C = (0, 4)

On translation of (x + 4, y - 3 ) the new angle A'B'C' will have new coordinate and as such, it will be:

A' = (0 + 4, 0 - 3)

B' = (-3 + 4, 1 - 3)

C' = (0 + 4, 4- 3)

So it will be:

A' = (4, -3)

B' = (1, -2)

C' = (4, 1)

Therefore, The new angle A 'B' C will be congruent to angle A,B,C, as it was just moved or shifted lightly 4 times and down 3 times.

Learn more about angle from

brainly.com/question/25716982

#SPJ1

You might be interested in

"Durable press" cotton fabrics are treated to improve their recovery from wrinkles after washing "Wrinkle recovery angle" measur

ludmilkaskok [199]

Answer:

At 5% there is significant evidence to reject the null hypothesis. You can conclude that there is a difference between the population mean of the wrinkle recovery angle of fabric treated with Permafresh and the population mean of the wrinkle recovery angle of fabric treated with Hylite.

X[bar]₁= 120.8 degrees

X[bar]₂= 162.75 degrees

S₁²= 14.5155 degrees

S₂²= 24.4727 degrees

Step-by-step explanation:

Hello!

The study variable is X: wrinkle recovery angle for a fabric specimen.

There is a suspicion that there is a difference in recovery from wrinkles after washing between two products (Permafresh and Hilite). To test this suspicion two random samples of fabric, 5 were treated with Permafresh and 4 were treated with Hylite resulting in the data:

Sample 1 (Permafresh)

X₁: wrinkle recovery angle for a fabric specimen treated with Permafresh.

X₁~N(μ₁;σ₁²)

n₁= 5

124; 104; 142; 111; 123

Sample mean X[bar]₁= (∑x₁i)/n₁= 604/5= 120.8 degrees

Sample variance S₁²= $\frac{1}{(n₁-1)}$ [(∑x₁²i)-(∑x₁i)²/n₁] = $\frac{1}{4}$ [(73806)-(604)²/5]= 210.7 degrees²

S₁= 14.515 ≅ 14.52 degrees

Sample 2 (Hylite)

X₂: wrinkle recovery angre for a fabric specimen trated with Hylite.

X₂~N(μ₂;σ₂²)

n₂= 4

147; 199; 149; 156

Sample mean X[bar]₂= (∑x₂i)/n₂= 651/4= 162.75 degrees

Sample variance S₂²= $\frac{1}{(n₂-1)}$ [(∑x₂²i)-(∑x₂i)²/n₂] = $\frac{1}{3}$ [(107747)-(651)²/4]= 598.916 ≅ 598.92 degrees²

S₂= 24.472≅ 24.47 degrees

To test the suspicion that there is a difference between the winkle recovery angle on fabric samples treated with Permafresh and Hylite, the hypothesis is:

H₀: μ₁ = μ₂

H₁: μ₁ ≠ μ₂

α: 0.05

To test the difference between the population means, considering that only sample information is available and the size of both samples, the most appropriate statistic to use is a pooled t for independent samples (unknown but equal population variances):

t= (X[bar]₁ - X[bar]₂) - (μ₁ - μ₂) ~t $_{n_1+n_2-2}$

Sa√(1/n₁+1/n₂)

Sa²= (n₁-1)S₁² + (n₂-1)S₂² = (4*210.7)+(3*598.92) = 377.08

n₁ + n₂ - 2 5+4-2

Sa= 19.418≅ 19.42

t= (X[bar]₁ - X[bar]₂) - (μ₁ - μ₂) = (120.8-162.75) - 0 = -3.22

Sa√(1/n₁+1/n₂) 19.42√(1/5+1/4)

Using the critical region approach, this rejection region is two-tailed with critical values:

$t_{n_1+n_2-2; \alpha/2 } = t_{7; 0.025 } = -2.365$

$t_{n_1+n_2-2; 1- \alpha/2 } = t_{7; 0.975 } = 2.365$

If t ≤ -2.365 or t ≥2.365, then the decision is to reject the null hypothesis.

If -2.365 < t < 2.365, then the decision is to not reject the null hypothesis.

Since the calculated t-value is less than the left critical value, the decision is to reject the null hypothesis.

I've calculated the p-value for the test: 0.0146

This p-value is less than the significance level of 0.05, then, using this approach, the decision is also to reject the null hypothesis.

This means, that at 5% there is significant evidence to reject the null hypothesis. You can conclude that there is a difference between the population mean of the wrinkle recovery angle of fabric treated with Permafresh and the population mean of the wrinkle recovery angle of fabric treated with Hylite.

I hope it helps!

4 0

4 years ago

Over what interval is the graph of y=−2 +|x− 2| increasing?

Zepler [3.9K]

Answer:

(2, ∞)

Step-by-step explanation:

An absolute value graph at (0, 0) is an up facing V shape graph. After a few transformation, according to the equation y = −2 + |x− 2|, we have our vertex at (0, - 2). It remains at up facing V graph.

x - h,

x - 2,

x - (+ 2),

h = 2

Therefore our slope is 2, with out vertex at (0, - 2). If we plot our graph, you can see that on the interval (2, ∞) the graph increases...

6 0

4 years ago

A boy collects a total of 316 stamps, stickers and coins altogether. He collects 4 times as many stamps as stickers. There are 4

madam [21]

Answer:

270 i tink it is the answer

8 0

3 years ago

Read 2 more answers

Stephen and Rocco were playing video games Stephen scored 2,500 points which is 5 time's as many points as Rocco scored how many

pantera1 [17]

Answer:

500 points

Step-by-step explanation:

Rocco scored 1/5 as many points as Stephen, so scored ...

(1/5) × (2500 points) = 500 points

Rocco scored 500 points.

6 0

3 years ago

Please help! 2 people have already stolen my brainlist :(

Damm [24]

Answer:

a). xy

b).x^2

c). (2y-1) (y^2+3)

7 0

2 years ago