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inn [45]
3 years ago
5

Stephen and Rocco were playing video games Stephen scored 2,500 points which is 5 time's as many points as Rocco scored how many

points did Rocco score
Mathematics
1 answer:
pantera1 [17]3 years ago
6 0

Answer:

  500 points

Step-by-step explanation:

Rocco scored 1/5 as many points as Stephen, so scored ...

  (1/5) × (2500 points) = 500 points

Rocco scored 500 points.

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Apartment A has a security deposit of $1000 and cost $1200 each month. Apartment B has a $1500 security deposit and cost $1175 e
Rom4ik [11]
1000 + 1200m = 1500 + 1175m
1200m - 1175m = 1500 - 1000
25m = 500
m = 500/25
m = 20 <== they are the same at 20 months...they will both be 25,000
7 0
3 years ago
Phoebe has 4 bags of cat food. She feeds her cat 1/5 of a bag
Annette [7]

Answer:

20 days

Step-by-step explanation:

5 days for each bag becuase each day is 1/5 5 days=5/5 (1 whole).

there are 4 bag so we do 5*4=20.

It would take 20 days to finsih all the bags.

PLEASE GIVE BRAINLIEST

6 0
2 years ago
Read 2 more answers
Distribute the expression. <br><br> 5(2<br> s<br> 2<br> −3s+4)
Nookie1986 [14]

If it's just distribution, not solving for s (I mean I could but do you need to?):

5(2s² - 3s + 4)     Distribute/multiply 5 into (2s² - 3s + 4)

(5)2s² - (5)3s + (5)4

10s² - 15s + 20

8 0
3 years ago
A binomial probability distribution has p = .20 and n = 100.
AleksAgata [21]

Answer:

Mean = 0.2(100) = 20

Variance = 0.2×0.8×100 = 16

Standard deviation = 4

Yes, np > 5 & nq > 5

3 0
3 years ago
Read 2 more answers
A closed, rectangular-faced box with a square base is to be constructed using only 36 m2 of material. What should the height h a
kkurt [141]

Answer:

b=h=\sqrt{6} m

Step-by-step explanation:

Let

Bas length of box=b

Height of box=h

Material used in constructing of box=36 square m

We have to find the height h and base length b of the box to maximize the volume of box.

Surface area of box=2b^2+4bh

2b^2+4bh=36

b^2+2bh=18

2bh=18-b^2

h=\frac{18-b^2}{2b}

Volume of box, V=b^2h

Substitute the values

V=b^2\times \frac{18-b^2}{2b}

V=\frac{1}{2}(18b-b^3)

Differentiate w. r.t b

\frac{dV}{db}=\frac{1}{2}(18-3b^2)

\frac{dV}{db}=0

\frac{1}{2}(18-3b^2)=0

\implies 18-3b^2=0

\implies 3b^2=18

b^2=6

b=\pm \sqrt{6}

b=\sqrt{6}

The negative value of b is not possible because length cannot be negative.

Again differentiate w.r.t b

\frac{d^2V}{db^2}=-3b

At  b=\sqrt{6}

\frac{d^2V}{db^2}=-3\sqrt{6}

Hence, the volume of box is maximum at b=\sqrt{6}.

h=\frac{18-(\sqrt{6})^2}{2\sqrt{6}}

h=\frac{18-6}{2\sqrt{6}}

h=\frac{12}{2\sqrt{6}}

h=\sqrt{6}

b=h=\sqrt{6} m

7 0
3 years ago
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