Answer:
Is it going to be $19.55?
Step-by-step explanation:
Ok, so you are given the value of P=q+2
The substitution method tells us that we must insert the value we know, into the second equation, 4P+3q= -27
Doing so will give us 4(q+2)+3q= -27
For right now, lets just focus on the first part, 4(q+2)
We can simplify this by distributing(multiplying) the 4 to whats inside the variables.
This will give us 4q+8
now lets add this back to the rest of the equation >>> 4q+8+3q = -27
We can further simplify by adding like terms >>> 7q+8 = -27
subtract the 8 from both sides >>> 7q = -35
now divide both sides by 7 >>> q = -35/7
Therefor q = -5
EDIT*
now that we know q = -5 we can put q into the equation for P !
we know that p=q+2
so lets put q in now >>> p=(-5)+2
and simplify>>> p = -3
I hope this helps:)
Answer:
Step-by-step explanation:
1 Us pint = 16 Us fluid ounces
It means that 8 pints of water would be
8 × 16 = 128 fluid ounces
Each batch of lemonade uses 24 fluid ounces of lemon juice and 8 pints of water. The total number of fluid ounces in each batch is
128 + 24 = 152 fluid ounces
Also,
1 fluid ounce = 0.125 Us cups
Therefore, the number of cups made is
152 × 0.125 = 19 cups
If each serving is 1 cup, then the number of servings that she made from each batch of lemonade is 19
servings. The number of batches made is 6. Therefore, the number of servings made altogether is
6 × 19 = 114
If her brother came and spilled half of it on the floor, then the number of servings that she have left after that for her party is
114/2 = 57 servings
the answer is B. 7
Step-by-step explanation:
it's the number u see the most therefore its the most common
Answer: true
Step-by-step explanation:
Z-tests are statistical calculations that can be used to compare the population mean to a sample mean The z-score is used to tellsbhow far in standard deviations a data point is from the mean of the data set. z-test compares a sample to a defined population and is typically used for dealing with problems relating to large samples (n > 30). Z-tests can also be used to test a hypothesis. Z-test is most useful when the standard deviation is known.
Like z-tests, t-tests are used to test a hypothesis, but a t-test asks whether a difference between the means of two groups is not likely to have occurred because of random chance. Usually, t-tests are used when dealing with problems with a small sample size (n < 30).
Both tests (z-tests and t-tests) are used in data with normal distribution (a sample data or population data that is evenly distributed around the mean).
