Answer:
150
Step-by-step explanation:
3 times 50 equal 150
Complete question:
The growth of a city is described by the population function p(t) = P0e^kt where P0 is the initial population of the city, t is the time in years, and k is a constant. If the population of the city atis 19,000 and the population of the city atis 23,000, which is the nearest approximation to the population of the city at
Answer:
27,800
Step-by-step explanation:
We need to obtain the initial population(P0) and constant value (k)
Population function : p(t) = P0e^kt
At t = 0, population = 19,000
19,000 = P0e^(k*0)
19,000 = P0 * e^0
19000 = P0 * 1
19000 = P0
Hence, initial population = 19,000
At t = 3; population = 23,000
23,000 = 19000e^(k*3)
23000 = 19000 * e^3k
e^3k = 23000/ 19000
e^3k = 1.2105263
Take the ln
3k = ln(1.2105263)
k = 0.1910552 / 3
k = 0.0636850
At t = 6
p(t) = P0e^kt
p(6) = 19000 * e^(0.0636850 * 6)
P(6) = 19000 * e^0.3821104
P(6) = 19000 * 1.4653739
P(6) = 27842.104
27,800 ( nearest whole number)
Answer choice B is correct
solving equation in terms of x we get 
solving equation in terms of y we get 
Step-by-step explanation:
We need to solve the equation: 
Solving the equation:
Simplifying and finding value of x:
We can simplify and find value of y as well:
So, solving equation in terms of x we get
solving equation in terms of y we get
Keywords: Solving Equations
Learn more about Solving Equations at:
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Answer:
-0.55 + 0.53a
Step-by-step explanation:
-0.55 – 0.47a + a
To find an expression equivalent to this, we must simplify the equation to a reasonable extent;
-0.55 – 0.47a + a
= -0.55 + 0.53a
= 0.53a - 0.55
The expression equivalent to the given one is -0.55 + 0.53a or 0.53a - 0.55
