Answer:
The shortest side = 6
The third side = 9
The hypotenuse (the longest side) = 16
Step-by-step explanation:
First, let's establish the following based on the information given:
The shortest side = x
The third side = (x + 3)
The hypotenuse (the longest side) = (2x + 4)
The perimeter = 31
Since the perimeter is the total of all 3 sides, we are left with this equation:
(x) + (x + 3) + (2x + 4) = 31
From here, combine like-terms and solve for x.
(x) + (x + 3) + (2x + 4) = 31
(4x + 7) = 31
4x = 24
x = 6
Now that we know the value of x, we can apply this to the predetermined formulas to find the measurements of the remaining two sides.
The shortest side = 6
The third side = (x + 3) = 9
The hypotenuse (the longest side) = (2x + 4) = (2(6) + 4) = (12 + 4) = 16
To check, add all of the sides together to make sure they equal 31.
6 + 9 + 16 = 31
~Hope this Helps!~
Answer: $20
Step-by-step explanation:
Let 'x' be the cost of a ticket at Haynes
Let 'y' be the cost of a ticket at Valley
Since the total cost from both schools are the same, we can write it as:
Since the cost of tickets at Valley was $5 less than Haynes, we can write it as:
Now we have two equations, we can use to substitute into the other expression:
we substitute y in this equation with the other equation
Therefore the cost of the ticket at Haynes is $20 and the cost of the ticket at Valley is $15.
Answer:
-273c
Step-by-step explanation:
Answer:
m∠V ≈ 61°
Step-by-step explanation:
The hypotenuse and the side opposite the angle of interest are given. The relevant trig relation is ...
Sin = Opposite/Hypotenuse
sin(V) = XW/XV = 7/8
The inverse sine function is used to find the angle:
V = arcsin(7/8) ≈ 61°
If you need the geometry and trigonometry I'll post those. Instead I found an answer at this link: http://jwilson.coe.uga.edu/EMAT6450/Class%20Projects/Scarpelli/Scarpelli_MathematicsBaseballActivity.....
The distance from home plate to the pitcher's mound is 60.5 feet and from home plate to second base is <span>127.28 feet.
Pitcher's Mound to 2nd base = </span><span>
<span>
<span>
66.78</span> </span>f</span>eet
Given those distances, we KNOW a 50 foot sprinkler will NOT reach home plate and second base from the pitcher's mound.
I didn't figure out the pitcher's mound to 1st or to 3rd, since the question is already answered.
