A quadrilateral is ____ a parallelogram

2 answers:

5 0

Quadrilateral=4 sided figure
paralellogram=4 sided figure with 2 pairs of paralell sides

answer is sometimes

a trapezoid is a quadrilateral but not a paralellogram
a square is a quadrilateral and a paralellogram

answer is sometimes

grandymaker [24]4 years ago

3 0

I believe it's always a parallelogram??

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Need help with this

Anon25 [30]

Answer:

See below.

Step-by-step explanation:

2a + 3 * (1 + 2) = 2a + 9: Yes. Expression is equivalent.

33v = (3 * v) * 11: Yes. Expression is equivalent.

3b - 19 + 2b = 3b + 19 - 2b: No. Both expressions are different answers.

4(3c - 4) = 2(6c - 8): No. expressions are not equivalent.

3 0

3 years ago

Can you plz help me with number one

inysia [295]

Answer: C. 2

Step-by-step explanation:

5 0

3 years ago

Verify the identity tan(???? − ????) = tan(????)−tan(????) / 1+tan (????) tan(????) for all (???? − ????) ≠ ???? / 2 + ????n.

Anna11 [10]

Answer:

See the proof below.

Step-by-step explanation:

For this case we need to proof the following identity:

$tan(x-y) = \frac{tan x - tan y}{1 + tan x tan y}$

So we need to begin with the definition of tan, we know that $tan x = \frac{sin x}{cos x}$ and we have this:

$tan (x-y) = \frac{sin(x-y)}{cos(x-y)}$ (1)

We also have the following identities:

$sin (a-b) = sin a cos b - sin b cos a$

$cos(a-b) = sin a sin b + cos a cos b$

And if we apply those identities into equation (1) we got:

$tan(x-y) = \frac{sin x cos y - sin y cos x}{sin x sin y + cos x cos y}$ (2)

We can divide numerator and denominator from expression (2) by $\frac{1}{cos x cos y}$ like this:

$tan(x-y) = \frac{\frac{sin x cos y}{cos x cos y} - \frac{sin y cos x}{cos x cos y}}{\frac{sin x sin y}{cos x cos y} + \frac{cos x cos y}{cos x cos y}}$