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4 years ago

14

Terrell runs two timed drills at practice the first drill takes 33.5 Seconds and the second drill takes 28.2 seconds .how much t

ime does he take him to complete both drills

2 answers:

Advocard [28]4 years ago

7 0

61.7 seconds
33.5+28.2=61.7

Nuetrik [128]4 years ago

4 0

The answer is 61.7 seconds because if you do 33.5 seconds +20.2 seconds you look at 61.7 :-) :-)

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Number 10 please a and b

LuckyWell [14K]

Answer:

28 - 14 = 14

IM NOTSURE IF THIS IS WHAT YOU WERE LOOKING FOR BUT WHATEVER I TRYED

7 0

4 years ago

39/51 change to lowest terms

OLEGan [10]

Answer:

As a proper fraction - 39/51 = 13/17

As a decimal number: 39/51 ≈ 0.76

As a percentage: 39/51 ≈ 76.47%

Step-by-step explanation:

Calculate the greatest (highest) common factor (divisor), gcf (gcd).

13/17 =

13 ÷ 17 =

0.764705882353 ≈

0.76

By precentage

0.764705882353 =

0.764705882353 × 100/100 =

76.470588235294/100 =

76.470588235294% ≈

76.47%

7 0

3 years ago

A blood sample with a known glucose concentration of 102.0 mg/dL is used to test a new at home glucose monitor. The device is us

Soloha48 [4]

Answer:

The Absolute Error is the difference between the actual and measured value.

$Absolute \:error = |Actual \:value - Measured \:value|$

The Relative Error is the Absolute Error divided by the actual measurement.

$Relative \:error = \frac{Absolute \:error}{Actual \:value}$

We know that the actual value is 102.0 mg/dL.

To find the absolute error and relative error for each measurement made by the glucose monitor you must use the above definitions.

a) For a concentration of 104.5 mg/dL the absolute error and relative error are

$Absolute \:error = \left|102-104.5\right|\\Absolute \:error =\left|-2.5\right|\\Absolute \:error =2.5$

$Relative \:error = \frac{2.5}{102.0}=0.0245$

b) For a concentration of 96.2 mg/dL the absolute error and relative error are

$Absolute \:error = \left|102.0-96.2\right|\\Absolute \:error =\left|5.8\right|\\Absolute \:error =5.8$

$Relative \:error = \frac{5.8}{102.0}=0.0569$

c) For a concentration of 102.2 mg/dL the absolute error and relative error are

$Absolute \:error = \left|102.0-102.2\right|\\Absolute \:error =\left|-0.2\right|\\Absolute \:error =0.2$

$Relative \:error = \frac{0.2}{102.0}=0.00196$

d) For a concentration of 98.3 mg/dL the absolute error and relative error are

$Absolute \:error = \left|102.0-98.3\right|\\Absolute \:error =\left|3.7\right|\\Absolute \:error =3.7$

$Relative \:error = \frac{3.7}{102.0}=0.0363$

e) For a concentration of 101.8 mg/dL the absolute error and relative error are

$Absolute \:error = \left|102.0-101.8\right|\\Absolute \:error =\left|0.2\right|\\Absolute \:error =0.2$

$Relative \:error = \frac{0.2}{102.0}=0.00196$

4 0

3 years ago

9+3.5g=11-0.5g brainliest to whoever gives steps

kow [346]

Answer:

The answer is <u>g = 0.5</u>

Step-by-step explanation:

1. Your equation is :

<em>9+3.5g=11-0.5g</em>

2. First, multiply both sides by ten

<em>9 * 10 + 3.5 * 10 = 11 * 10 - 0.5 * 10</em>

3. Next we refine the equation

<em>90 + 35g = 110 - 5g</em>

4. Now, lets subtract 90 from both sides

<em>90 + 35g - 90 = 110 - 5g - 90</em>

5. Simplify

<em>35g + 5g = -5g + 20 + 5g</em>

6. We then add 5g to both sides

<em>35g + 5g = -5g + 20 + 5g</em>

7. Simplify again

<em>40g = 20</em>

8. Now, divide both sides by 40

<em>40g/40 = 20/40</em>

9. And finally, simplify once again to get your final answer.

<em>g = 1/2 or 0.5</em>

I hope this helped :)

7 0

3 years ago

What is the missing statement in step 10 of the proof?

telo118 [61]

Answer:

c/sin C = b/sin C

Step-by-step explanation:

Look at the statement in the previous step and the reason in this step.

c sin B = b sin C

Divide both sides by sin B sin C:

(c <em>sin B</em>)/(<em>sin B</em> sin C) = (b <em>sin C</em>)/(sin B <em>sin C</em>)

c/sin C = b/sin B

7 0

3 years ago