D = {f, g, k}
1 answer:
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So this is just working with exponents, but negative exponents can be a little tricky. your example didn't do a great job of showing how you calculate negative exponents.
for #2, you have 10⁻⁶
to convert negative exponents into something that makes more sense to our brain, you can set it beneath 1:
... or, in the event that you can't see that because you're on the app: (1)/(10⁶). so now, instead of calculating 10⁻⁶, which would probably give you a confusing decimal, you just need to figure out 10⁶ -- and positive exponents are much easier to deal with.
10⁶ = 1,000,000
BUT remember that you have to put this value beneath a 1 to account for your negative exponent and (1/1,000,000) is your answer for part A.
so, use the same steps for the rest of the problems:
1) convert negative exponent to positive exponent beneath 1
7⁻³ = (1)/(7³)
2) calculate 7³
7³ = 343
<span>3) your result is (1/343)
</span>
<span>for 12</span>⁻², again, you'll put it beneath 1 so that it becomes (1)/(12²), then you'll calculate 12² (12*12 = 144), so that your result is (1/144). that leaves the letter D for number 2, which you'll have to write into your boxes at the top.
i hope this helps! you can message me if you have any specific ones that cause you trouble and i'll do my best to help.
for #2, you have 10⁻⁶
to convert negative exponents into something that makes more sense to our brain, you can set it beneath 1:
10⁶ = 1,000,000
BUT remember that you have to put this value beneath a 1 to account for your negative exponent and (1/1,000,000) is your answer for part A.
so, use the same steps for the rest of the problems:
1) convert negative exponent to positive exponent beneath 1
7⁻³ = (1)/(7³)
2) calculate 7³
7³ = 343
<span>3) your result is (1/343)
</span>
<span>for 12</span>⁻², again, you'll put it beneath 1 so that it becomes (1)/(12²), then you'll calculate 12² (12*12 = 144), so that your result is (1/144). that leaves the letter D for number 2, which you'll have to write into your boxes at the top.
i hope this helps! you can message me if you have any specific ones that cause you trouble and i'll do my best to help.