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Serhud [2]
2 years ago
15

Solve for Q-392 = 28q​

Mathematics
1 answer:
poizon [28]2 years ago
5 0

Answer:

14

Step-by-step explanation:

-392=28q

-392÷28=14

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You deposit 600$ in a savings account.the account earns 10% simple interest per year
Zepler [3.9K]
You would have $660. The trick for 10% of something is to move the decimal one place to the left. The decimal is “hidden” to the right of the last 0. Add that interest on to get your answer!! Good luck!
5 0
2 years ago
Find the area bounded by the graphs of the indicated equations over the given interval.
NeX [460]

Answer:

48

Step-by-step explanation:

y = 0

is basically the horizontal axis.

First, find the integral of x^2-25.

Remember that

integral of a constant is that constant times x.

Also that

to take the integral of a power function, add 1 to the degree and divide by that same degree.

y =  {x}^{2}  - 25

We then get

\frac{ {x}^{3} }{3}  - 25x

Evaluate at -3

\frac{ - 3 {}^{3} }{3}  - 25( - 3)

- 27 + 75 = 48

Then we evaluate at 0

\frac{0 {}^{3} }{3}  - 25(0) = 0

Next, we subtract the the answer then we get

48 - 0 = 48

8 0
2 years ago
joe spends $8 on lunch and $6.50 on dry cleaning. He also buys 2 shiets that cost the same amount. joe spendes a total of $52. w
ANEK [815]
X=amout the shirts cost
52=8+6.50+2x
add 8 and 6.5
52=14.5+2x
subtract 14.5 from 52
37.5=2x
divide 37.5 by 2
x=18.75
It cost $18.75 for each shirt.
4 0
2 years ago
The combustion of one gallon of automobile fuel produces about 5 pounds of carbon (in CO₂). Two autos are making a trip of 600 m
rewona [7]

Answer:

Approximately 50 pounds less carbon (in CO₂) will be produced by the second auto on this trip.

Step-by-step explanation:

We have been given that the combustion of one gallon of automobile fuel produces about 5 pounds of carbon (in CO₂). Two autos are making a trip of 600 miles.

Let us find amount of fuel used by autos by dividing the total distance by their mileage.

\text{Fuel used by 1st auto}=\frac{\text{ 600 miles}}{\frac{\text{ 20 miles}}{\text{gallon}}}

\text{Fuel used by 1st auto}=\frac{\text{ 600 miles}}{\text{ 20 miles}}\times \text{gallon}

\text{Fuel used by 1st auto}=30 \text{ gallons}

\text{Fuel used by 2nd auto}=\frac{\text{ 600 miles}}{\frac{\text{ 30 miles}}{\text{gallon}}}

\text{Fuel used by 2nd auto}=\frac{\text{ 600 miles}}{\text{ 30 miles}}\times \text{gallon}

\text{Fuel used by 2nd auto}=20 \text{ gallons}

Let us find the difference of fuel used by both autos.

\text{Number of gallons that 2nd auto used less than 1st auto}=30-20

\text{Number of gallons that 2nd auto used less than 1st auto}=10

Since one gallon of automobile fuel produces about 5 pounds of carbon, so 10 gallons of fuel will produces 5\times 10=50 pounds of carbon.

Since 2nd auto used 10 gallons less than 1st auto, therefore, 2nd auto will produce 50 pounds less carbon than 1st auto.

8 0
3 years ago
The average temperature in Calgary, Canada, is 22 degrees celsius in July and -11 degrees celsius in January. Find the range of
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The range is positive 11° Celsius
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3 years ago
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