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Serhud [2]
3 years ago
15

Solve for Q-392 = 28q​

Mathematics
1 answer:
poizon [28]3 years ago
5 0

Answer:

14

Step-by-step explanation:

-392=28q

-392÷28=14

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PLS HELP ASAP ILL GIVE BRAINLKEST
Alenkasestr [34]

Answer:

Its the bottom one x>5

Step-by-step explanation:

8 0
2 years ago
Jesse served 13 pints of orange juice at her party how many quarts of orange juice did she serve
Alexus [3.1K]

Answer:

26 pints

Step-by-step explanation:

1 quart = 2 pints

13*2=26


5 0
3 years ago
3a-2b=50, 2a+3b=100 what does a equal and what does b equal?
harina [27]
A = (350/13) and B = (400/-13)
7 0
2 years ago
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Lunch break: In a recent survey of 655 working Americans ages 25-34, the average weekly amount spent on lunch was $43.5
Inga [223]

Using the Empirical Rule, it is found that:

  • a) Approximately 99.7% of the amounts are between $35.26 and $51.88.
  • b) Approximately 95% of the amounts are between $38.03 and $49.11.
  • c) Approximately 68% of the amounts fall between $40.73 and $46.27.

------------

The Empirical Rule states that, in a <em>bell-shaped </em>distribution:

  • Approximately 68% of the measures are within 1 standard deviation of the mean.
  • Approximately 95% of the measures are within 2 standard deviations of the mean.
  • Approximately 99.7% of the measures are within 3 standard deviations of the mean.

-----------

Item a:

43.5 - 3(2.77) = 35.26

43.5 + 3(2.77) = 51.88

Within <em>3 standard deviations of the mean</em>, thus, approximately 99.7%.

-----------

Item b:

43.5 - 2(2.77) = 38.03

43.5 + 2(2.77) = 49.11

Within 2<em> standard deviations of the mean</em>, thus, approximately 95%.

-----------

Item c:

  • 68% is within 1 standard deviation of the mean, so:

43.5 - 2.77 = 40.73

43.5 + 2.77 = 46.27

Approximately 68% of the amounts fall between $40.73 and $46.27.

A similar problem is given at brainly.com/question/15967965

8 0
2 years ago
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You invest $300 at 4% interest, compounded every year. What will your balance be after 5 years? (Remember, the formula is A = P(
Stells [14]

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill\\ P=\textit{original amount deposited}\to &\$300\\ r=rate\to 4\%\to \frac{4}{100}\to &0.04\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{every year, once} \end{array}\to &1\\ t=years\to &5 \end{cases} \\\\\\ A=300\left(1+\frac{0.04}{1}\right)^{1\cdot 5}\implies A=300(1.04)^5\implies A\approx 364.996

3 0
3 years ago
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