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3 years ago

10

Which table represents the same relation as the set StartSet (negative 6, 4), (negative 4, 0), (negative 3, 2), (negative 1, 2)

EndSet?

2 answers:

g100num [7]3 years ago

5 0

Negative 4,0 because I know it

maks197457 [2]3 years ago

4 0

Answer:

Graph b

Step-by-step explanation:

ED2020

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Which is the angle measure represented by 7.5 rotations clockwise?

kondaur [170]

Recall that 1 rotation is the equivalent of 360 degrees or 2pi radians.

7.5 rotations clockwise 2pi rad
------------------------------- * ---------------------------------------
1 1 rotation counterclockwise

= -47.12 radians, or -2700 degrees.

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4 years ago

Which ordered pair is a solution for the system of equations? {3x−5y=152x−y=−4 (−5, −6) (0, 3) (2, 8) (−6, −11)

SashulF [63]

3x-5y =15

2x-y=-4
multiply the equation by 5 and then subtract equation 2 from equation 1
so 3x-5y =15
10x-5y =-20
-7x =35 x =-5
plug in the value of x in the second equation -10 -y =-4 - y= -4 +10 y =-6
x=-5 y=-6

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4 years ago

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Simplify (5+1)^2-(11+3^2) divided by four

telo118 [61]

Answer: 6

Step-by-step explanation:

(5+1)^2-(11+3^2)

25+1-11+9

26-20

=6

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4 years ago

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The area of the regular hexagon is 169.74 ft2 what is the perimeter, rounded to the nearest tenth

Bess [88]

Answer:

Perimeter of given regular hexagon is <em>48.5 ft</em>.

Step-by-step explanation:

Let <em>ABCDEF</em> be the regular hexagon as shown in the attached figure.

<em>O</em> be the intersection point of the diagonals <em>EB</em>, <em>FC </em>and <em>AD</em>.

As per the property of regular hexagon, all the 6 triangles formed are equilateral triangles.

In other words,

$\triangle EOD, \triangle DOC, \triangle BOC, \triangle AOB, \triangle AOF , \triangle FOE$ are equilateral $\triangle s$ .

Area of an equilateral $\triangle$ is defined as :

$\dfrac{\sqrt{3}}{4} \times a^{2}$

Where <em>a </em>is the side of $\triangle$ .

Area of hexagon = $6 \times \dfrac{\sqrt{3}}{4}\times a^{2}$

We are given that area of hexagon = 169.74 $ft^{2}$

Let <em>s </em>be the side of hexagon.

$\Rightarrow 6 \times \dfrac{\sqrt{3}}{4}s^{2} = 169.74 ft^{2}\\\Rightarrow s = 8.08 ft$

A regular Hexagon is made up of 6 equal sides, so

Perimeter of a regular hexagon = $6 \times side$

Perimeter = $6 \times 8.08$

$\Rightarrow 48.5 ft$

So, perimeter of given regular hexagon is $48.5 ft$ .

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