Area=legnth times width
so multiply them together use distributive property
a(b+c)=ab+ac so
in this problem
(a+b)(c+d+e)=(a+b)(c)+(a+b)(d)+(a+b)(e)
so
x^2-2 times (2x^2-x+2)=(x^2)(2x^2-x+2)-(2)(2x^2-x+2)=(2x^4-x^3+2x^2)-(4x^2-2x+4)
add like terms
2x^4-x^3+(2x^2-4x^2)-2x+4
2x^4-x^3-2x^2-2x+4
Answer:
1
Step-by-step explanation:
You will be multiplying 1 into 2. You then subtract 1 from 2.
which will give you 1= x
98 isnt a prime, which means that it is a composite number
Answer:
Step-by-step explanation:
Assuming we want to find the equation (74,2) and (4,9)
This is an equation of a straight.
Let this equation be y=mx+b.
We substitute the slope and (4,9) to get:
We rewrite in standard form to get: