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Fed [463]
2 years ago
7

3. A mass spectrometer is an instrument that can be used to determine the mass of a substance. A student measured the mass of 3

samples. The expected mass was 568.4g. The 3 measurements were 548.5 g, 548.9 g, and 548.7 g. Is this random or systematic error
Mathematics
1 answer:
Tju [1.3M]2 years ago
3 0

The error that occurred is a systematic error.

<h3>What is random error?</h3>

Random error is a type of error that causes one measurement to differ slightly from the next.

<h3>What is systematic error?</h3>

Systematic error is a type of error that affects measurements in the same amount or by the same proportion, provided that readings are taken in the same way.

The three measurements 548.5 g, 548.9 g, and 548.7 g differ slightly but in the same amount and proportion.

Therefore, a systematic error occurred during the determination of the mass of the substance because the readings were taken in the same way and the measurement differ in the same amount.

Read more about error in measurement here:

https://brainly.in/question/9800276

#SPJ1

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A rectangle has vertices E(4,8), F(2,8), G(2,-2) and H(-4,-2). The rectangle is dilated with the origin as the center of dilatio
Leona [35]

Note: The image of G after the dilation must be G'(5,-5) instead of G'(5,5).

Given:

The vertices of a rectangle are E(4,8), F(2,8), G(2,-2) and H(-4,-2).

The rectangle is dilated with the origin as the center of dilation so that G's is located at (5,-5).

To find:

The algebraic representation that represents this dilation.

Solution:

If a figure is dilated by factor k with origin as the center of dilation, then the dilation is defined as:

(x,y)\to (kx,ky)              ...(i)

Let the given rectangle is dilated by factor k with origin as the center of dilation. Then,

G(2,-2)\to G'(k(2),k(-2))

G(2,-2)\to G'(2k,-2k)

The image of G after dilation is G'(5,-5). So,

(2k,-2k)=(5,-5)

On comparing both sides, we get

2k=5

k=\dfrac{5}{2}

So, the scale factor is k=\dfrac{5}{2}.

Substituting k=\dfrac{5}{2} in (i), we get

(x,y)\to \left(\dfrac{5}{2}x,\dfrac{5}{2}y\right)

Therefore, the required algebraic representation to represents this dilation is (x,y)\to \left(\dfrac{5}{2}x,\dfrac{5}{2}y\right).

3 0
3 years ago
How do I solve this?
Alex787 [66]

- 5.3 \geqslant 6.7 + 4.3 + q \\  - 5.3 \geqslant 11 + q \\  - 5.3 - 11 \geqslant q \\  - 16.3 \geqslant q
5 0
3 years ago
Quantos centímetros há em 60 m ?<br>​
artcher [175]
Ndheueksmzhhsjsiskzkdoee
3 0
3 years ago
Does anyone have the answers for all?
Shkiper50 [21]

Answer and Step-by-step explanation:

1-6

a.

What you can do is plug in 6 and start by doing the first machine first, then the second. If this doesn't work, do the second machine, then the first machine.

<em><u>The order that works is second machine, then first machine.</u></em>

<u>Second Machine:</u>

y = (6)^{2} -6 = 36 - 6 = 30

Plug into first machine now.

<u>First Machine:</u>

y = \sqrt{(30) - 5}  = \sqrt{25} = 5

We see that the result is 5.

b. <em><u>If we were to do the order of second machine, then first machine, we will never get a negative result (or -5 for that matter), due to the fact that you can't algebraically square root a negative number.</u></em>

<em><u>However, if we were to do the order of first machine, second machine, we can get a negative number. To get -5, we plug in 6 for x in the first machine, getting an answer of 1. We plug this into the second machine, getting 1^2 - 6, which results in -5.</u></em>

1-7. The absolute value of a value is the positive version of that value.

a. |54| = <em><u>54</u></em>

b. -|-7\frac{3}{5}| = -7\frac{3}{5}

c. |3| - |-1| = 3 - 1 = <em><u>2</u></em>

d. |2.2 - 5.13| = |-2.93| = <em><u>2.93</u></em>

1-8.

a.

_

<u>|  |</u>

<u>|  |</u>

<u>|  |</u>

<u>|  |</u>

<u>|  |</u> <u>  </u> <u>   </u> <u>  </u> <u>   </u>

<u>|  ||  ||  ||  ||  |</u>

<u>(5 boxes on each side)</u>

_

<u>|  |</u>

<u>|  |</u>

<u>|  |</u>

<u>|  |</u>

<u>|  |</u> <u>  </u> <u>   </u> <u>  </u> <u>   </u> <u>   </u>

<u>|  ||  ||  ||  ||  ||  |</u>

<u>(6 boxes on each side)</u>

b.<em><u> The amount of squares on each side of the figure increases by 1.</u></em>

c. <em><u>There would be 1 square, because we know that the pattern is there is 2 squares added to the next figure, 1 at each end. If we go back a figure, we take away 2 squares.</u></em>

1-9.

a. -42 - 17 = <em><u>-59</u></em>

b. 8 - (-9) = 8 + 9 = <em><u>17</u></em>

c. 8(-9) = <em><u>-72</u></em>

d. -42 ÷ (-7) = <em><u>6</u></em>

e. -2(-3)(-4) = 6(-4) = <em><u>24</u></em>

f. -18 - 7 = <em><u>-25</u></em>

g. (-5)^{2} = <em><u>25</u></em>

h. -5^{2}  = -(5)^2 = -(25) = <em><u>-25</u></em>

i. \sqrt{49} = <em><u>7</u></em>

1-10.  x = 2 Plug 2 in for x, then solve.

a. y = 7 - 3(2) = 7 - 6 = <em><u>1</u></em>

b. y = (2)^2 -1 = 4 - 1 = <em><u>3</u></em>

c. y = \frac{18}{2} = <em><u>9</u></em>

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

<em><u>I hope this helps!</u></em>

8 0
3 years ago
I need help who wanna help me? what is 1000× 10000?​
mr_godi [17]

Answer:

10000000

Step-by-step explanation:

3 0
3 years ago
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