<h2>
For a = 1 and b = 10 x+1 and x+2 factors of x³-ax²-bx-8 = 0</h2><h2>
Other factor is (x-4)</h2>
Step-by-step explanation:
We have
x³-ax²-bx-8 = 0
Its factors are x+1 and x+2
That is x = -1 and x = -2 are its roots
Substituting x = -1
(-1)³-a(-1)²-b(-1)-8 = 0
-1 - a + b - 8 = 0
b - a = 9 ---------------------eqn 1
Substituting x = -2
(-2)³-a(-2)²-b(-2)-8 = 0
-8 - 4a + 2b - 8 = 0
2b - 4a = 16 ---------------------eqn 2
eqn 1 x -2
-2b + 2a = -18 ---------------------eqn 3
eqn 2 + eqn 3
-2a = -2
a = 1
Substituting in eqn 1
b - 1 = 9
b = 10
For a = 1 and b = 10, x+1 and x+2 factors of x³-ax²-bx-8 = 0
The equation is x³-x²-10x-8 = 0
Dividing with x + 1 we will get
x³-x²-10x-8 = (x+1)(x²-2x-8)
Dividing (x²-2x-8) with x + 2 we will get
x²-2x-8 = (x+2)(x-4)
So we have
x³-x²-10x-8 = (x+1)(x+2)(x-4)
Other factor is (x-4)
Answer: it’s not clear I can’t see it
Step-by-step explanation:
Answer:
The first and third options are the examples of exponential functions.
Step-by-step explanation:
When a quantity is compounded after a certain interval of time at a certain rate, then we can assume that the situation can be represented by an exponential function.
In the first option: An event organizer finds each year's attendance for the past five years is about 
of previous year's attendance.
So, here the total attendance is compounding every year by a factor of previous year's attendance.
Again, in the third case: The total population is increasing by about 7.5% each year.
Hence, the population is compounded every year by 7.5% of the previous year's population.
Therefore, the first and third options are examples of exponential functions. (Answer)
Answer:
x=-2;y=-7
Step-by-step explanation:
y=5x+3
y=3x-1
3x-1=5x+3
-2x=4
x=-2 y=5x+3 y=5×(-2)+3 y=-7
Answer:
2
Step-by-step explanation:
13x2=26
14x3=42
Greatest common Factor of 26 and 42 is 2
