Answer:
As the points are collinear, the slope of the line joining
any two points, should be same as the slope of the line joining two other
points.
Slope of the line passing through points (x
1
,y
1
) and (x
2
,y
2
) =
x
2
−x
1
y
2
−y
1
So, slope of the line joining (p,0),(0,q)= Slope of the line joining
(0,q) and (1,1)
0−p
q−0
=
1−0
1−q
−
p
q
=1−q
Dividing both sides by q,
−
p
1
=
q
1
−1
=>
p
1
+
q
1
=1
A is the answer because the key word is TOTAL and EACH
There is no rate of change of Function 1. It's slope(rate of change) is zero.
Function 2 has a slope of 2.
Note: The height of the room must be 3 m instead of 3 cm because 3 cm is too small and it cannot be the height of a room.
Given:
Perimeter of the floor of a room = 18 metre
Height of the room = 3 metre
To find:
The area of 4 walls of the room.
Solution:
We know that, the area of 4 walls of the room is the curved surface area of the cuboid room.
The curved surface area of the cuboid is

Where, h is height, l is length and b is breadth.
Perimeter of the rectangular base is 2(l+b). So,

Putting the given values, we get


Therefore, the area of 4 walls of the room is 54 sq. metres.
Essentially 11(4d + 6) = 11*4d + 6*11
44d + 66