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3 years ago

Jeff has 4 red pens and 2 blue pens in his backpack. He also has 1 yellow highlighter and 4 green highlighters in his

Mathematics

2 answers:

zvonat [6]3 years ago

7 0

Answer:

2/15

Step-by-step explanation:

Romashka-Z-Leto [24]3 years ago

3 0

Answer:

$\frac{1}{15}$

Step-by-step explanation:

In probability,

"AND" means "multiplication"

"OR" means "ADDITION"

We want probability of Blue Pen and Yellow Highlighter. So we find individual probabilities and "MULTIPLY" them.

Let P(b) be probability of blue pen

Let P(y) be probability of yellow highlighter

We know probability of event is that event divided by total number of that

So,

There are 4 + 2 = 6 pens

Blue pen = 2

Hence,

P(b) = 2/6 = 1/3

And,

There are 5 highlighters

Yellow highlighter = 1

Hence,

P(y) = 1/5

Now,

P(b and y) = 1/3 * 1/5 = 1/15

Hence,

probability of grabbing blue pen and a yellow highlighter is $\frac{1}{15}$

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I NEED HELP PLEASE :(

Studentka2010 [4]

Answer:

7/8

Step-by-step explanation:

power of 1/2 is the same as square root.

√(49/64) = 7/8 since 7/8 * 7/8 = 7*7/8*8 = 49/64

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3 years ago

Pls I need it for a testI’ll give out 20 points

kompoz [17]

Answer:

It should be D.

Step-by-step explanation:

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2 years ago

Suppose that 7 female and 5 male applicants have been successfully screened for 5 positions. If the 5 positions are filled at ra

katen-ka-za [31]

Answer:

(a) 350

(b) 175

(d) 196

Step-by-step explanation:

Number of females = 7

Number of males = 5

Total ways of selecting r items from n items is

$^nC_r=\dfrac{n!}{r!(n-r)!}$

(a)

Total ways of selecting 3 females and 2 males.

$\text{Total ways}=^7C_3\times ^5C_2$

$\text{Total ways}=\dfrac{7!}{3!(7-3)!}\times \dfrac{5!}{2!(5-2)!}$

$\text{Total ways}=35\times 10$

$\text{Total ways}=350$

(b)

Total ways of selecting 4 females and 1 male.

$\text{Total ways}=^7C_4\times ^5C_1$

$\text{Total ways}=32\times 5$

$\text{Total ways}=175$

(c)

Total ways of selecting 5 females.

$\text{Total ways}=^7C_5\times ^5C_0$

$\text{Total ways}=21\times 1$

$\text{Total ways}=21$

(d)

Total ways of selecting at least 4 females.

Total ways = 4 females + 5 females

$\text{Total ways}=175+21$

$\text{Total ways}=196$

6 0

3 years ago

Maximal use of bezels, gradients, and drop shadows make an interface highly user friendly True False

tigry1 [53]

Bezels, gradients, and drop shadows can make an interface user-friendly if used wisely and minimally. If too much, the interface can be distracting. The problem used the term "maximal." This means that the bezels, gradients, and drop shadows are excessively used in an interface. So, the answer to this question is
FALSE
Using too much image effects can make an interface not user-friendly.<span />

5 0

3 years ago

Please help I found this one a bit confusing

Brums [2.3K]

Answer:

7.2

Step-by-step explanation:

To reach point D from point C, you need to add 4 to the x-value of point C and take away 6 from the y-value. These numbers are the sides of the hypothetical triangle.

The Pythagorean Theorem states that $a^2+b^2=c^2$ . If we plug the side lengths in for a and b, we get $4^2 + 6^2 = c^2$ . This can be simplified to $16+36=c^2$ , or $52 = c^2$ . If we root both sides, we find that c is equal to $\sqrt{52}$ , which is slightly more than 7, at around 7.2.

4 0

2 years ago