All categories

3 years ago

I will give brainliest for question! How many nonzero terms are in the expansion of (x+4)(2x^2+3x+9)-3(x^3-2x^2+7x)?

Mathematics

1 answer:

nataly862011 [7]3 years ago

4 0

Answer:

Four

Step-by-step explanation:

Let's expand and see how many nonzero terms:

⇒ (x+4)(2x²+3x+9)-3(x³-2x²+7x)=

⇒ 2x³ + 3x² + 9x + 8x² + 12 + 36 - 3x³ + 6 x² - 21 x=

⇒ - x³ + 17x² - 12x + 12

As we see the expression has four nonzero terms

You might be interested in

Point P partitions directed segment AB in the ratio of 3:4.

trapecia [35]

Answer:

Total number of congruent sections/parts = 7

$k = \frac{3}{7}$

Step-by-step explanation:

Given that partitions directed segment AB such that AP : PB = 3 : 4, this implies that:

There are 7 parts/congruent sections that AB has been divided into.

Also, point P, partitions AB in the ratio 3:4.

Therefore, there are a total of 7 congruent sections/parts.

Value of k:

Value of k = numerator of the original ratio ÷ sum of numerator and denominator of the original ratio

$k = \frac{3}{3 + 4}$

$k = \frac{3}{7}$

6 0

4 years ago

Equation point-slope form y=4x+17

umka21 [38]

Answer:

I think it's y - 21 = 4 (x - 1)

Step-by-step explanation:

im sorry if it's wrong

5 0

2 years ago

What do you notice what do you wonder

bixtya [17]

I wonder if theres any other earths

8 0

3 years ago

9-127 Nicole has three long logs. She wants to place them in a

navik [9.2K]

Answer:

The logs do not form a right-angle triangle

Step-by-step explanation:

Given

$Logs: 9ft, 11ft, 21ft$

Required

Do the logs form a right-angled triangle

Applying Pythagoras theorem

$a^2 = b^2 + c^2$

Where a is the length of the longest log.

So, we have:

$21^2 = 9^2 + 11^2$

$441 = 81 + 121$

$441 \ne 202$

The above shows an inequality.

Hence, the logs do not form a right-angle triangle

5 0

4 years ago

The manager of a national park determines that the park can sustain 81 coyotes. The manager assumes that the rate of change of t

Katena32 [7]

Answer:

$N(T) = \frac{81*40*e^{1.075t}}}{81 + 40*(e^{1.075t} - 1)}$

Step-by-step explanation:

This problem can be solved by the logistic equation of populations, that is:

$N(t) = \frac{KN_{0}e^{rt}}}{K + N_{0}(e^{rt} - 1)}$

In which K is the carrying capacity of the population, $N_{0}$ is the initial population, r is the decimal growth rate and t is the period of time.

In this problem, we have that:

When t = 0, the population is 40: This means that $N_{0} = 40$ .

The manager of a national park determines that the park can sustain 81 coyotes. This means that $K = 81$ .

When t = 1, the population has increased to 60. This means that $N(1) = 60$ .

To write the equation, we have to find the value of r.

$N(t) = \frac{KN_{0}e^{rt}}}{K + N_{0}(e^{rt} - 1)}$

$60 = \frac{81*40*e^{r}}}{81 + 40*(e^{r} - 1)}$

$60*(41 + 40e^{r}) = 3240e^{r}$

$2460 + 2400e^{r} = 3240e^{r}$

$840e^{r} = 2460$

$e^{r} = 2.93$

Now we apply ln to both sides, and:

$r = 1.075$

The answer is:

$N(T) = \frac{81*40*e^{1.075t}}}{81 + 40*(e^{1.075t} - 1)}$

8 0

4 years ago