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erastova [34]
2 years ago
9

Which statement is true about a scientific law?

Chemistry
1 answer:
Yakvenalex [24]2 years ago
6 0
C. It is a relationship that is supported by experiments
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Relacione la teoria cuantica con el numero cuantico correspondite
Xelga [282]
“relate the quantum theory to the corresponding quantum number” what is your quantum number
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3 years ago
What are Valence Electrons?
Gekata [30.6K]
Valence electrons are the electrons that are in an atom's outermost layer. 
Every atom is made of protons, neutrons, and electrons.
Electrons are outside them both.
They have energy levels (number of electrons per layer)
And the number they have on the farthest layer are the valence electrons. 

5 0
3 years ago
Read 2 more answers
A solution of ammonia and water contains 1.50×10^25 water molecules and 8.20×10^24 ammonia molecules. How many total hydrogen at
Evgesh-ka [11]
In order to compute the total hydrogen atoms present, we must first write the molecular formulas of ammonia and water to know how many hydrogen atoms are present in each molecule.

Water - H₂O; so 2 hydrogen atoms per molecule of water

Ammonia - NH₃; so 3 hydrogen atoms per molecule of ammonia

Total hydrogen atoms = 2 * molecules of water + 3 * molecules of ammonia

H atoms = 2 * 1.5 x 10²⁵ + 3 * 8.2 x 10²⁴
H atoms = 5.46 x 10²⁵

There are a total of 5.46 x 10²⁵ hydrogen atoms in the solution
3 0
3 years ago
6. How many moles are represented by 11.5 g of C2H5OH?
polet [3.4K]

Answer:

n C2H5OH = 0.2496 mol

Explanation:

  • moles (n) = mass / molecular weight

∴ m C2H5OH = 11.5 g

∴ Mw C2H5OH = (2)(12.011) + (6)(1.00794) +  15.9994 = 46.069 g/mol

⇒ n C2H5OH = (11.5 g)/(46.069 g/mol) = 0.2496 mol C2H5OH

5 0
3 years ago
Two chemicals a and b are combined to form a chemical
dedylja [7]
-dB/dt = kAB = k(2B)(B) = 2kB^2
-dB/B^2 = 2kdt
Integrating: 1/B - 1/(B_0) = 2kt
At t = 10, if 15 g of C have formed, this must have consumed 10 g A and 5 g B. The remaining mass of B is 45 g.
1/45 - 1/50 = 2(k)(10)
k = 1.11 x 10^-4
Then substituting this value of k with t = 40:
1/B - 1/50 = 2(1.11 x 10^-4)(40)
1/B - 1/50 = 0.008889
1/B = 0.028889
B = 34.62 g remaining
Therefore, 50 - 34.62 = 15.38 g of B have been consumed.
Doubling, 30.76 g of A have been consumed.
This means that 15.38 + 30.76 = 46.15 g of C have been formed.
5 0
3 years ago
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