“relate the quantum theory to the corresponding quantum number” what is your quantum number
Valence electrons are the electrons that are in an atom's outermost layer.
Every atom is made of protons, neutrons, and electrons.
Electrons are outside them both.
They have energy levels (number of electrons per layer)
And the number they have on the farthest layer are the valence electrons.
In order to compute the total hydrogen atoms present, we must first write the molecular formulas of ammonia and water to know how many hydrogen atoms are present in each molecule.
Water - H₂O; so 2 hydrogen atoms per molecule of water
Ammonia - NH₃; so 3 hydrogen atoms per molecule of ammonia
Total hydrogen atoms = 2 * molecules of water + 3 * molecules of ammonia
H atoms = 2 * 1.5 x 10²⁵ + 3 * 8.2 x 10²⁴
H atoms = 5.46 x 10²⁵
There are a total of 5.46 x 10²⁵ hydrogen atoms in the solution
Answer:
n C2H5OH = 0.2496 mol
Explanation:
- moles (n) = mass / molecular weight
∴ m C2H5OH = 11.5 g
∴ Mw C2H5OH = (2)(12.011) + (6)(1.00794) + 15.9994 = 46.069 g/mol
⇒ n C2H5OH = (11.5 g)/(46.069 g/mol) = 0.2496 mol C2H5OH
-dB/dt = kAB = k(2B)(B) = 2kB^2
-dB/B^2 = 2kdt
Integrating: 1/B - 1/(B_0) = 2kt
At t = 10, if 15 g of C have formed, this must have consumed 10 g A and 5 g B. The remaining mass of B is 45 g.
1/45 - 1/50 = 2(k)(10)
k = 1.11 x 10^-4
Then substituting this value of k with t = 40:
1/B - 1/50 = 2(1.11 x 10^-4)(40)
1/B - 1/50 = 0.008889
1/B = 0.028889
B = 34.62 g remaining
Therefore, 50 - 34.62 = 15.38 g of B have been consumed.
Doubling, 30.76 g of A have been consumed.
This means that 15.38 + 30.76 = 46.15 g of C have been formed.