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3 years ago

3k(k+10)=0 factor show steps please

Mathematics

1 answer:

saul85 [17]3 years ago

7 0

Answer:

Simplifying

3k(k + 10) = 0

Reorder the terms:

3k(10 + k) = 0

(10 * 3k + k * 3k) = 0

(30k + 3k2) = 0

Solving

30k + 3k2 = 0

Solving for variable 'k'.

Factor out the Greatest Common Factor (GCF), '3k'.

3k(10 + k) = 0

Ignore the factor 3.

Subproblem 1

Set the factor 'k' equal to zero and attempt to solve:

Simplifying

k = 0

Solving

k = 0

Move all terms containing k to the left, all other terms to the right.

Simplifying

k = 0

Subproblem 2

Set the factor '(10 + k)' equal to zero and attempt to solve:

Simplifying

10 + k = 0

Solving

10 + k = 0

Move all terms containing k to the left, all other terms to the right.

Add '-10' to each side of the equation.

10 + -10 + k = 0 + -10

Combine like terms: 10 + -10 = 0

0 + k = 0 + -10

k = 0 + -10

Combine like terms: 0 + -10 = -10

k = -10

Simplifying

k = -10

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Read 2 more answers

Iq scores are normally distributed with a mean of 100 and a standard deviation of 15.

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Mean is $\mu=100$ and a standard deviation is $\sigma =15$ , then the variable $X\sim N(100,15^2)$ .

Use substitution

$Z=\dfrac{X-\mu}{\sigma},\\ \\ Z=\dfrac{X-100}{15}$ .

This substitution gives you that $Z\sim N(0,1)$ .

a. For X=130, $Z=\dfrac{130-100}{15}=2$ and $Pr(X>130)=Pr(Z>2) =0.9772$ (the decimal value is taken from the Standard Normal Distribution Table).

b. For X=90, $Z=\dfrac{90-100}{15}=-\dfrac{2}{3}$ and for X=110, $Z=\dfrac{110-100}{15}=\dfrac{2}{3}$ . Then $Pr(90$ (the decimal value is taken from the Standard Normal Distribution Table).