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IrinaK [193]
2 years ago
10

Answer please hahahahhaha​

Mathematics
1 answer:
levacccp [35]2 years ago
7 0

\dfrac{5-i}{4+3i}=\dfrac{(5-i)(4-3i)}{(4+3i)(4-3i)}=\dfrac{20-15i-4i-3}{16+9}=\dfrac{17-19i}{25}=\dfrac{17}{25}-\dfrac{19}{25}i

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Un curso esta formado por 12 mujeres y 15 hombres ¿cual es la probabilidad de que las personas en el cargo de presidente y visep
riadik2000 [5.3K]

Answer:

P = (12/27)*(11/26) = 0.188

Step-by-step explanation:

Si todos tienen la misma probabilidad de estar en cargo de presidente y vicepresidente, entonces:

La probabilidad de que una mujer sea presidente, es igual al cociente entre el número de mujeres y el número total de personas:

p = 12/27

Ahora queremos calcular lo mismo para vicepresidente, y el cálculo es exactamente igual, con la diferencia de que en esta situación, ya hay una mujer en el cargo de presidente, entonces hay 11 mujeres que pueden ser vicepresidente, y un total de: (11 + 15 = 26 personas)

Entonces ahora la probabilidad es:

q = 11/26

La probabilidad conjunta (es decir, la probabilidad de que ambos eventos pasen) es igual al producto de las probabilidades individuales.

P = (12/27)*(11/26) = 0.188

4 0
3 years ago
Select all the statements that apply to the concept of a residual
skelet666 [1.2K]

Answer:

first and second one, and fourth one

Step-by-step explanation:

4 0
3 years ago
Which is the best estimate for the area of the circle shown below?
Elza [17]

Answer:

c) 380 m²

Step-by-step explanation:

A = π·r²

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3 0
3 years ago
Read 2 more answers
We learned in that about 69.7% of 18-20 year olds consumed alcoholic beverages in 2008. We now consider a random sample of fifty
maw [93]

Answer:

(1) The expected number of people who would have consumed alcoholic beverages is 34.9.

(2) The standard deviation of people who would have consumed alcoholic beverages is 10.56.

(3) It is surprising that there were 45 or more people who have consumed alcoholic beverages.

Step-by-step explanation:

Let <em>X</em> = number of adults between 18 to 20 years consumed alcoholic beverages in 2008.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.697.

A random sample of <em>n</em> = 50 adults in the age group 18 - 20 years is selected.

An adult, in the age group 18 - 20 years, consuming alcohol is independent of the others.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 50 and <em>p</em> = 0.697.

The probability mass function of a Binomial random variable <em>X</em> is:

P(X=x)={50\choose x}0.697^{x}(1-0.697)^{50-x};\ x=0,1,2,3...

(1)

Compute the expected value of <em>X</em> as follows:

E(X)=np\\=50\times 0.697\\=34.85\\\approx34.9

Thus, the expected number of people who would have consumed alcoholic beverages is 34.9.

(2)

Compute the standard deviation of <em>X</em> as follows:

SD(X)=\sqrt{np(1-p)}=\sqrt{50\times 0.697\times (1-0.697)}=10.55955\approx10.56

Thus, the standard deviation of people who would have consumed alcoholic beverages is 10.56.

(3)

Compute the probability of <em>X</em> ≥ 45 as follows:

P (<em>X</em> ≥ 45) = P (X = 45) + P (X = 46) + ... + P (X = 50)

                =\sum\limits^{50}_{x=45} {50\choose x}0.697^{x}(1-0.697)^{50-x}\\=0.0005+0.0001+0.00002+0.000003+0+0\\=0.000623\\\approx0.0006

The probability that 45 or more have consumed alcoholic beverages is 0.0006.

An unusual or surprising event is an event that has a very low probability of success, i.e. <em>p</em> < 0.05.

The probability of 45 or more have consumed alcoholic beverages is 0.0006. This probability value is very small.

Thus, it is surprising that there were 45 or more people who have consumed alcoholic beverages.

6 0
3 years ago
When trying to find the best deal for items, you should ____
kodGreya [7K]
Question 1:

All provided options would give the best deal on an item

Answer: Option d [all of the above]

Question 2:

When an item's price is knocked off by 15%, it means the item has only 85% of its original value left to pay. Hence, a discount of 15% means multiplying the original price by 85%

Answer: option C
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3 years ago
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