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2 years ago

Answer please hahahahhaha

Mathematics

1 answer:

levacccp [35]2 years ago

7 0

$\dfrac{5-i}{4+3i}=\dfrac{(5-i)(4-3i)}{(4+3i)(4-3i)}=\dfrac{20-15i-4i-3}{16+9}=\dfrac{17-19i}{25}=\dfrac{17}{25}-\dfrac{19}{25}i$

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Answer please hahahahhaha​

Answer please hahahahhaha