Cos^2A+cos^2A*cot^2A=cot^2A
1 answer:
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Answer:
Cost of a snack size bag of chips = $0.8
Cost of a water bottle = $1.6
Cost of a gallon of milk = $3.4
Step-by-step explanation:
Let the cost of water bottle = $a
Cost of 1 gallon milk = $b
and cost of 1 bag of chips = $c
So, cost of 4 gallons of milk, 6 bottles of water and 5 bags of chips = $(4b + 6a + 5c)
4b + 6a + 5c = 27.2 -----(1)
Cost of one water bottle = 2 × cost of one bag of chips
a = 2c -----(2)
A gallon of milk = cost of water bottle + $1.80
b = a + 1.8
From equation (2)
b = 2c + 1.8 -----(3)
Now we substitute these values from equations (2) and (3) in equation (1)
4(2c + 1.8) + 6(2c) + 5c = 27.2
8c + 7.2 + 12c + 5c = 27.2
25c = 27.2 - 7.2
c =
c = $0.8
From equation (2)
a = 2×0.8
a = $1.6
From equation (3)
b = 2(0.8) + 1.8
b = 1.6 + 1.8
b = $3.4
Therefore, cost of a snack size bag of chips = $0.8
Cost of a water bottle = $1.6
Cost of a gallon of milk = $3.4
Answer:
There is some mistake in the question, because the solutions are x = -1.445 and x = -34.555
Step-by-step explanation:
Given the functions:
f(x) = x² + 4x + 10
g(x) = -32x - 40
we want to find the points at which f(x) = g(x).
x² + 4x + 10 = -32x - 40
x² + 4x + 10 + 32x + 40 = 0
x² + 36x + 50 = 0
Using quadratic formula: