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2 years ago

Cos^2A+cos^2A*cot^2A=cot^2A

1 answer:

4 0

LHS: cos^2 A( 1+cot^2A)
=cos^2A(cosec^2A) ,1+cot^2A=cosec^2A
=cos^2A( 1/sin^2A)
=(cos^2A/ sin^2A)
=cot^2A
=RHS

Hope this can help.

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A cylinder and a come have the same volume. The cylinder has a radius of 2 inches and a height of 3 inches. The cone has radius

MrRissso [65]

Answer: 4in

Step-by-step explanation:

Volume of a cylinder = πR²H

Volume of a cone = 1/3πr²h

πR²H = 1/3πr²h

π is very common so it could be cancelled, so the equation now becomes

R²H = 1/3r²h

3R²H = r²h

Now substitute for the values

h = 3 x 2² x 3

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2 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

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2 years ago

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3 years ago

The inches of rainfall in the rainforest is represented by the function f(x) = 3(x-2)+ 4. What is the average rate of change bet

nata0808 [166]

Answer:

The average rate of change of rainfall in the rainforest between 2nd year and 6th year = <u>3 inches</u>

Step-by-step explanation:

Given function representing inches of rainfall:

$f(x)=3(x-2)+4$

To find the average rate of change between the 2nd year and the 6th year.

Solution:

The average rate of change between interval $[a,b]$ is given as :

$\frac{f(b)-f(a)}{b-a}$

For the given function we need to find the average rate of change between 2nd year and 6th year. $[2,6]$

So, we have:

$f(2)=3(2-2)+4=3(0)+4=4$

$f(6)=3(6-2)+4=3(4)+4=12+4=16$

Thus, average rate of change will be:

$\frac{f(6)-f(2)}{6-2}$

⇒ $\frac{16-4}{6-2}$

⇒ $\frac{12}{4}$

⇒ $3$

Thus, the average rate of change of rainfall in the rainforest between 2nd year and 6th year = 3 inches

8 0

3 years ago

Cos^2A+cos^2A*cot^2A=cot^2A​

Cos^2A+cos^2A*cot^2A=cot^2A