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2 years ago

Landon used a semicircle, a rectangle, and a right triangle to form the figure shown.

Mathematics

1 answer:

pashok25 [27]2 years ago

3 0

I believe the answer is 10

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Simplify 7 + (−3). a. −10 b. −4 c. 4 d. 10

Vikentia [17]

C. Your Answer Is 4. Which Is C

3 0

3 years ago

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Find all real solutions of this equation to answer

Lera25 [3.4K]

Answer:

(6-2x)(3-2x)x=40

Step-by-step explanation:

(-2x-2x) (6+3)x=40

8x=40

8x/8=40/8

x=5

6 0

3 years ago

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Brandi needs to wrap a birthday present for her friend's party. Each side length is 16.7 in. What is the minimum amount of paper

tester [92]

A box has 6 sides so you multiply 16.7 and 6 and you’ll get 100.2
ANSWER IS 100.2in

3 0

2 years ago

Does anyone know how to solve this?

Bezzdna [24]

Use this version of the Law of Cosines to find side b:

b^2 = a^2 + c^2 − 2ac cos(B)

We want side b.

b^2 = (41)^2 + (20)^2 - 2(41)(20)cos(36°)

After finding b, you can use the Law of Sines to find angles A and C or use other forms of the Law of Cosines to find angles A and C.

Try it....

6 0

3 years ago

Hey how do you get from standard form to vertex form?

vlabodo [156]

Explanation:

Conversion of a quadratic equation from standard form to vertex form is done by completing the square method.

Assume the quadratic equation to be $\mathbf{ax^{2}+bx+c=0}$ where x is the variable.

Completing the square method is as follows:

send the constant term to other side of equal $\mathbf{ax^{2}+bx=-c}$
divide the whole equation be coefficient of $\mathbf{x^{2}}$ , this will give $\mathbf{x^{2}+\frac{b}{a}x=- \frac{c}{a}}$
add $\mathbf{(\frac{b}{2a})^{2}}$ to both side of equality $\mathbf{x^{2}+2\times\frac{b}{2a}x+\frac{b}{2a}^{2}=-\frac{c}{a}+\frac{b}{2a}^{2}}$
Make one fraction on the right side and compress the expression on the left side $\mathbf{(x+\frac{b}{2a})^{2}=\frac{b^{2}-4ac}{4a^{2}}}$
rearrange the terms will give the vertex form of standard quadratic equation $\mathbf{a(x+\frac{b}{2a})^{2}-\frac{b^{2}-4ac}{4a}=0}$

Follow the above procedure will give the vertex form.

(NOTE : you must know that $\mathbf{(x+a)^{2}=x^{2}+2ax+a^{2}}$ . Use this equation in transforming the equation from step 3 to step 4)

8 0

3 years ago