Answer:
-5/4
Step-by-step explanation:
Slope is rise over run which means that the -5 will apply to your y values and the 4 will apply to your x values. This slope would have a point move down 5 units and to the right 4 units to get the location of the next point when going left to right. Because the slope contains a negative, the slope will be angled downward left to right. The negative only applies to the 5.
Answer:
2) 45
3) 25
4) 50%
5) 33.3%
6) 17.6
7) 500
8) 35%
9) 60
10) 87.5%
11) 2.64
12) 25%
13) 5.7
14) 85%
16) 75%
Step-by-step explanation:
2) 9 = 20% of x
9 * 5 = 45
3) 8% of x = 2
12.5 * 2 = 25
4) 39 = x(78)
39/78 = 1/2 = 50%
5) x(36) = 12
12/36 = 1/3 = 33.3...%
6) x = 0.8(22)
22/10 = 2.2
2.2* 8 = 16 + 1.6 = 17.6
7) 55 = 0.11(x)
55/11 = 5
5 * 100 = 500
8) 7/20 = 35/100 = 35%
9) 27 = 0.45(x)
27/45 = 3/5
3/5 * 100 = 300/5 = 60
10) . 49/56 = 7/8 = 0.875 = 87.5%
11) 6/100 = 0.06
0.06 * 44 = 2.64
12) 48/192 = 6/24 = 1/4 = 25%
13) 95/100 = 0.95
0.95 * 6 = 5.40 + 0.3 = 5.7
14) 68/80 = 34/40 = 17/20 = 85%
16) 108/144 = 9/12 = 0.75 = 75%
If my answer is incorrect, pls correct me!
If you like my answer and explanation, mark me as brainliest!
-Chetan K
5/9(f-32)=c
5/9f+5/9*-32=c: step 1
5f/9-160/9=c: step 2
5f/9-160/9+160/9=c+160/9: step 3
5f/9=160/9*9+c*9: step 4
5f/5=160/5+9c/5: step 5
f=32+(9c/5): answer
Answer: 100
Step-by-step explanation:
Given : The lodhl diner offers a meal combination consisting of an appetizer, a soup, a main course, and a dessert.
There are 5 appetizers, 5 soups, 4 main courses, and 5 desserts.
Also, a dessert and a appetizer are not allowed to take together.
By Fundamental counting principal ,
Number of three-course meals with dessert and without appetizer :
(1)
Number of three-course meals with appetizer and without dessert :
(2)
Now, the number of meals with either dessert or appetizer :-
[Add (1) and (2)]
Hello from MrBillDoesMath
Answer:
The image provided shows the answer
Discussion:
m = 4 * p^2 - 3p + 7
is the direct translation of the problem statement
Done.
Thank you,
Mr. B
