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2 years ago

The options are 9 12 18

Mathematics

1 answer:

Alexeev081 [22]2 years ago

5 0

Answer:

Step-by-step explanation:

length× bredth× height=volume but in this case it is a cylinder so for length and bredth we will use radius. For the height the cylinder is half filled so its height will be 1m. then we will use the formula

l×b×h 3×3×1=9 So 9 is the answer ♥

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What units could you use to measure the height of a hexagonal prism?

konstantin123 [22]

No aswer for that question

4 0

3 years ago

Solve the equation 2x^2 + 4x - 39 to the nearest tenth.

Virty [35]

Answer:

cant be solved, when you try to you get

-1+78 = 77

which is

77 = 77

1=1

So cannot be factored

Step-by-step explanation:

8 0

3 years ago

The endpoints of CD are C(−4, 7) and D(0,−3).

tino4ka555 [31]

Midpoint =(\frac{x_{2}+x_{1}}{2},\frac{y_{2}+y_{1}}{2})

Answer:

Midpoints of line CD are (-2,2).

Step-by-step explanation:

The midpoints is given by

$Midpoint =(\frac{x_{2}+x_{1}}{2},\frac{y_{2}+y_{1}}{2})$

As given

The endpoints of CD are C(−4, 7) and D(0,−3).

Putting values in the above

$Midpoint =(\frac{0-4}{2},\frac{-3+7}{2})$

$Midpoint =(\frac{-4}{2},\frac{4}{2})$

Midpoints = (-2,2)

Therefore midpoints of line CD are (-2,2).

4 0

3 years ago

Read 2 more answers

a study of nickels showed that the standard deviation of the weight of nickels is 300 milligrams. A coin counter manufacture wis

cupoosta [38]

Using the z-distribution, a sample of 609 nickels has to be weighed.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

$\overline{x} \pm z\frac{\sigma}{\sqrt{n}}$

The margin of error is:

$M = z\frac{\sigma}{\sqrt{n}}$

In which:

$\overline{x}$ is the sample mean.

z is the critical value.

n is the sample size.

$\sigma$ is the standard deviation for the population.

For this problem, the parameters are:

$M = 20, \sigma = 300, z = 1.645$

We solve for n to find the sample size, then:

$M = z\frac{\sigma}{\sqrt{n}}$

$20 = 1.645\frac{300}{\sqrt{n}}$

$20\sqrt{n} = 1.645 \times 300$

$\sqrt{n} = 1.645 \times 15$

$(\sqrt{n})^2 = (1.645 \times 15)^2$

n = 608.9

Rounding up, a sample of 609 nickels has to be weighed.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

6 0

2 years ago

HELP FAST PLEASE fast!!!!!!!!!1

igor_vitrenko [27]

Answer:

A is the correct answer.

Step-by-step explanation:

3 0

3 years ago