Question

Does someone mind helping me with this problem? Thank you!

Answer 1

Let's simplify ~

$\qquad \sf \dashrightarrow \: \dfrac{10 - (3 \times 2 {}^{2} - 23) }{(1 + 10 {}^{2}) - {2}^{2} \times {5}^{2} }$

$\qquad \sf \dashrightarrow \: \dfrac{10 - (3 \times 4{}^{} - 23) }{(1 + 10 0{}^{}) - {4}^{} \times {25}^{} }$

$\qquad \sf \dashrightarrow \: \dfrac{10 - (12- 23) }{(10 1{}^{}) - {100}^{} }$

$\qquad \sf \dashrightarrow \: \dfrac{10 - ( - 11) }{1}$

$\qquad \sf \dashrightarrow \: 10 + 11$

$\qquad \sf \dashrightarrow \: 21$

Answer 2

$\frac{10-(3 \cdot 2^2 - 23)}{(1 + 10^2)-2^2 \cdot 5^2} =$

$10-\left(3\cdot \:2^2-23\right) =10-\left(-11\right) =21$

$\left(1+10^2\right)-2^2\cdot \:5^2 = 101-2^2\cdot \:5^2 = 101-4\cdot \:5^2 =101-4\cdot \:25 =101-100 = 1$

$=\frac{21}{1}$

$\frac{a}{1}= a$

$=21$

I hope I helped you!