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Strike441 [17]
3 years ago
14

If x = a sin teta and y = b cos teta

Mathematics
1 answer:
Marat540 [252]3 years ago
8 0
  • x= a sin theta
  • y=b sin theta

\\ \sf\longmapsto b^2x^2+a^2y^2

\\ \sf\longmapsto b^2(asin\Theta)^2+a^2(bcos\Theta)^2

\\ \sf\longmapsto b^2a^2sin^2\Theta+a^2b^2cos^2\Theta

\\ \sf\longmapsto a^2b^2(sin^2\Theta+cos^2Theta)

\\ \sf\longmapsto a^2+b^2(1)

\\ \sf\longmapsto a^2b^2

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Ted has a shelf that is 75/4 inches wide. How many books can Ted arrange on the shelf if each book is 5/4 inches thick?
Paladinen [302]
(75/4) / (5/4) = 
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6 0
3 years ago
The probability of winning a certain lottery is 1/77076 for people who play 908 times find the mean number of wins
Alex73 [517]

The mean is 0.0118 approximately. So option C is correct

<h3><u>Solution:</u></h3>

Given that , The probability of winning a certain lottery is \frac{1}{77076} for people who play 908 times

We have to find the mean number of wins

\text { The probability of winning a lottery }=\frac{1}{77076}

Assume that a procedure yields a binomial distribution with a trial repeated n times.

Use the binomial probability formula to find the probability of x successes given the probability p of success on a single trial.

n=908, \text { probability } \mathrm{p}=\frac{1}{77076}

\text { Then, binomial mean }=n \times p

\begin{array}{l}{\mu=908 \times \frac{1}{77076}} \\\\ {\mu=\frac{908}{77076}} \\\\ {\mu=0.01178}\end{array}

Hence, the mean is 0.0118 approximately. So option C is correct.

4 0
3 years ago
Select the correct answer.<br> Which statement is true?
dusya [7]

Answer:

third option is the correct

Step-by-step explanation:

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ycow [4]

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Step-by-step explanation:

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