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Strike441 [17]
3 years ago
14

If x = a sin teta and y = b cos teta

Mathematics
1 answer:
Marat540 [252]3 years ago
8 0
  • x= a sin theta
  • y=b sin theta

\\ \sf\longmapsto b^2x^2+a^2y^2

\\ \sf\longmapsto b^2(asin\Theta)^2+a^2(bcos\Theta)^2

\\ \sf\longmapsto b^2a^2sin^2\Theta+a^2b^2cos^2\Theta

\\ \sf\longmapsto a^2b^2(sin^2\Theta+cos^2Theta)

\\ \sf\longmapsto a^2+b^2(1)

\\ \sf\longmapsto a^2b^2

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If MN=14, NO=11, and QR=27, find the length of PQ. Round your answer to the nearest tenth if necessary. Figures are not necessar
allsm [11]

Answer:

PQ = 34.4

Step-by-step explanation:

First, we know that the angles in a triangle add up to 180 degrees. Therefore, angle M = 48 and angle R = 74

Next, because there is a corresponding angle in each triangle, they are similar. This means that the ratios between corresponding sides are the same. For example, the side opposite angle O (MN) over the side opposite angle R (PQ) is equal to the side opposite angle N (OM) over the side opposite angle Q (RP)

This can be written as MN/PQ = OM/RP. Note that both the numerators are on the same triangle, and MN and PQ correspond, as well as OM and RP.

We are given MN, NO, and QR. Because NO is opposite a 48 degree angle (angle M) as well as QR (angle P), we can say that NO/QR = another ratio of a pair of corresponding sides. Because we want to find PQ, and both PQ and MN are opposite 74 degree angles, we can say that

NO/QR = MN/PQ

Thus,

11/27 = 14/PQ

multiply both sides by PQ to remove a denominator

PQ * 11/27 = 14

multiply both sides by 27 to remove the other denominator

PQ * 11 = 14 * 27

divide both sides by 11 to isolate the PQ

PQ = 14 * 27 /11

PQ = 34.4

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