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Strike441 [17]
3 years ago
14

If x = a sin teta and y = b cos teta

Mathematics
1 answer:
Marat540 [252]3 years ago
8 0
  • x= a sin theta
  • y=b sin theta

\\ \sf\longmapsto b^2x^2+a^2y^2

\\ \sf\longmapsto b^2(asin\Theta)^2+a^2(bcos\Theta)^2

\\ \sf\longmapsto b^2a^2sin^2\Theta+a^2b^2cos^2\Theta

\\ \sf\longmapsto a^2b^2(sin^2\Theta+cos^2Theta)

\\ \sf\longmapsto a^2+b^2(1)

\\ \sf\longmapsto a^2b^2

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How do you slove 2/3 (9x -6) = 14
Ivanshal [37]

Answer:

x=3

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

2

3

(9x−6)=14

(

2

3

)(9x)+(

2

3

)(−6)=14(Distribute)

6x+−4=14

6x−4=14

Step 2: Add 4 to both sides.

6x−4+4=14+4

6x=18

Step 3: Divide both sides by 6.

6x

6

=

18

6

x = 3

5 0
3 years ago
Which of the following points lies on the line whose equation is y = 2x - 3?
mariarad [96]
It's supposed to be (0,-3) but I guess your answer should be A
6 0
3 years ago
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A regional airport, community college, and city hall building are located at the vertices
love history [14]

Answer:

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Step-by-step explanation:

8 0
3 years ago
Solve this system of equations. y = 5x +20 and y = -2x -8
Thepotemich [5.8K]

Answer:

y = 0

x = -4

( x, y ) = ( -4 , 0 )

Step-by-step explanation:

y = 5x + 20

y = -2x - 8

Substitute

5x + 20 = -2x - 8

Add 8 on both sides

5x + 20 + 8 = -2x - 8 + 8

5x + 28 = -2x

Subtract 5x on both sides

5x - 5x + 28 = -2x - 5x

28 = -7x

Divide by -7 on both sides

28/-7 = -7x/-7

-4 = x

Now that you have x, you can substitute it in one of the equations that was given to find the value of y.

y = 5x + 20

y = 5(-4) + 20

y = -20 + 20

y = 0

Or....

y = -2x - 8

y = -2(-4) - 8

y = 8 - 8

y = 0

They will both be 0 no matter what

Point form = ( -4, 0 )

Hope this helped

3 0
3 years ago
What is equal to n in this equation
IRISSAK [1]

Answer:

n = -45

Step-by-step explanation:

(n-5) /10 = -5

Multiply each side by 10

(n-5) /10 *10= -5*10

n-5 = -50

Add 5 to each side

n-5+5 = -50+5

n = -45

4 0
3 years ago
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