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1 year ago

Find the value of x.

Mathematics

1 answer:

Novay_Z [31]1 year ago

4 0

Answer:

Step-by-step explanation:

Remark

What you don't know and what makes the problem confusing, is that where to the given arcs start and end. So I am going to say that both arcs start from E and 119 ends at D, and 174 ends at F which means that the arc FD is not known, but it is not hard to find.

The total number of degrees from beginning to end is 360 degrees. The formula for finding FD is

Formula

FD = 360 - (174 - 119)

The formula for x is (ED - FD)/2

Solution

Arc FD = 360 - (174 - 119)

Arc FD = 67

So x = (119 - 67) / 2

x = 52 /2

x = 26

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3 years ago

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Answer:

See explanation below

Step-by-step explanation:

The best explanation is noticing that in order to get from the point R (12, 1) to the point Q (7, 4) we move 5 units to the left and 3 units up. And to go from point Q (7, 4) to point P (2, 7) we do exactly the same: move 5 units to the left and 3 units up. That means that these points are all connected via the same rate of change: - 3/5, which is in fact the slope of the line the three points belong to.

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3 years ago

In analyzing the city and highway fuel efficiencies of many cars and trucks, the mean difference in fuel efficiencies for the 60

Olegator [25]

Answer:

$7.38-1.96\frac{2.51}{\sqrt{601}}=7.18$

$7.38+1.96\frac{2.51}{\sqrt{601}}=7.58$

For this case the confidence interval is given by :

$7.18 \leq \mu \leq 7.58$

Step-by-step explanation:

Data provided

$\bar X=7.38$ represent the sample mean for the fuel efficiencies

$\mu$ population mean

s=2.51 represent the sample standard deviation

n=601 represent the sample size

Confidence interval

The formula for the confidence interval of the true mean is given by:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom for this case is given by:

$df=n-1=601-1=600$

The Confidence level for this case is 0.95 or 95%, and the significance level $\alpha=0.05$ and $\alpha/2 =0.025$ and the critical value is given by $t_{\alpha/2}=1.96$

Replcing into the formula for the confidence interval is given by:

$7.38-1.96\frac{2.51}{\sqrt{601}}=7.18$

$7.38+1.96\frac{2.51}{\sqrt{601}}=7.58$

For this case the confidence interval is given by :

$7.18 \leq \mu \leq 7.58$

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3 years ago

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