Simplify ab + ab - bc

How do you graph a circle x^2 + y^2=25 and the line is given y=2

Kazeer [188]

$\bf \textit{equation of a circle}\\\\ 
(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
\qquad 
\begin{array}{lllll}
center\ (&{{ h}},&{{ k}})\qquad 
radius=&{{ r}}
\end{array}\\\\
-------------------------------\\\\
x^2+y^2=25\implies (x-0)^2+(y-0)^2=5^2$

so notice above, the circle is centered at h,k or 0,0, the origin, and has a ratio of 5.

and y = 2, is just a horizontal line, check the picture below.

7 0

3 years ago

3. Nutrition labels. The nutrition label on a bag of potato chips says that a one ounce (28 gram) serving of potato chips has 13

svetoff [14.1K]

Answer:

The 95% confidence interval of for this random sample is between 128.16 calories and 139.84 calories. This means that we are 95% that the mean number of calories for all bags of potato chips is in this interval.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 35 - 1 = 34

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 34 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.95}{2} = 0.975$ . So we have T = 2.0322

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 2.0322\frac{17}{\sqrt{35}} = 5.84$

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 134 - 5.84 = 128.16 calories

The upper end of the interval is the sample mean added to M. So it is 134 + 5.84 = 139.84 calories

The 95% confidence interval of for this random sample is between 128.16 calories and 139.84 calories. This means that we are 95% that the mean number of calories for all bags of potato chips is in this interval.

3 0

3 years ago

In a survey of 1,532 former UF students, 84% said they were still in love with Tim Tebow. The survey's sampling error was 2%. Us

nalin [4]

Answer:

confidence interval for the proportion of all former UF students who are still in love with Tim Tebow.

(0.79 , 0.89)

Step-by-step explanation:

step 1:-

Given sample survey former UF students n = 1532

84% said they were still in love with Tim Tebow

p = 0.84

The survey sampling error

$= \sqrt{\frac{p(1-p)}{n} }$

Given standard error of proportion = 2% =0.02

Step 2:-

The 99% of z- interval is 2.57

The 99% of confidence intervals are

p ± zₐ S.E (since sampling error of proportion = $\sqrt{\frac{pq}{n} }$

$(0.84 - 2.57X0.02 , 0.84 + 2.57X0.02)$

on simplification , we get

(0.84 - 0.0514 , 0.84 + 0.0514)

(0.79 , 0.89)

conclusion:-

confidence interval for the proportion of all former UF students who are still in love with Tim Tebow.

(0.79 , 0.89)

4 0

3 years ago

What is the area of the surface cone rounded to the nearest tenth?

EleoNora [17]

Answer:

A = 422.4

i promise it's right :)

4 0

2 years ago

Please help, ASAP!!

babymother [125]

Answer:

The answer should be x ≤ 5

3 0

2 years ago

Simplify ab + ab - bc - ab + bc