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kramer
3 years ago
14

A cube has a surface area of 200 square inches. Which choice is closest to the length of an edge of the cube?

Mathematics
2 answers:
Vikentia [17]3 years ago
6 0

Answer:

5.8

Step-by-step explanation:


Mrrafil [7]3 years ago
3 0
<span>A cube has 6 square faces, so each face would have area 200 sq in/6=33.33 sq in
Since the area of each face equals the square of the sides, the edge of the cube would be = approx. 5.77 in</span>
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FrozenT [24]
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5 0
3 years ago
Factor completely x^3 + 1/8
maksim [4K]

Answer:

((2 x + 1) (4 x^2 - 2 x + 1))/8

Step-by-step explanation:

Factor the following:

x^3 + 1/8

Put each term in x^3 + 1/8 over the common denominator 8: x^3 + 1/8 = (8 x^3)/8 + 1/8:

(8 x^3)/8 + 1/8

(8 x^3)/8 + 1/8 = (8 x^3 + 1)/8:

(8 x^3 + 1)/8

8 x^3 + 1 = (2 x)^3 + 1^3:

((2 x)^3 + 1^3)/8

Factor the sum of two cubes. (2 x)^3 + 1^3 = (2 x + 1) ((2 x)^2 - 2 x + 1^2):

((2 x + 1) ((2 x)^2 - 2 x + 1^2))/8

1^2 = 1:

((2 x + 1) ((2 x)^2 - 2 x + 1))/8

Multiply each exponent in 2 x by 2:

((2 x + 1) (2^2 x^2 - 2 x + 1))/8

2^2 = 4:

Answer:  ((2 x + 1) (4 x^2 - 2 x + 1))/8

5 0
3 years ago
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Write a recursive rule for the arithmetic sequence 22,15,8,1
lara31 [8.8K]

Answer:

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Step-by-step explanation:

7 0
3 years ago
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Answer:

The required point is P(-7,\frac{-7}{2}) where, x-coordinate twice the y-coordinate on line 2x - 6y = 7

Step-by-step explanation:

Given equation of line is 2x-6y=7

To find point on graph whose x-coordinate twice the y-coordinate:

Let y be y-coordinate of point

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The required point is P(2y,y) on equation of line 2x-6y=7

Now,

2x-6y=7

2(2y)-6y=7

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y=\frac{-7}{2}

Thus,

The required point is P(-7,\frac{-7}{2})

Note: Figure show equation of line red line and point P as blue dot.

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3 years ago
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Step-by-step explanation:
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3 years ago
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