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3 years ago

Did I get this right?

Mathematics

1 answer:

shusha [124]3 years ago

4 0

Answer:

y=56m

Step-by-step explanation:

choose any given points on both diagrams

30/48=35/y

cross multiply

30y=1680

y=1680/30=56m

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The daily high temperatures, in degrees Celsius, during one week were recorded as follows: −3°, −10°, 6°, 4°, −7°, −8°, −3°. Fin

Zarrin [17]

Answer:

-3

Step-by-step explanation:

average the numbers

7 0

3 years ago

What is .0091 rounded to the hundredths

-BARSIC- [3]

.0091 rounded to the nearest hundredths is .01.

3 0

4 years ago

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Write the values in the boxes that make the statement true

nikklg [1K]

Answer:

$\frac{5}{3}xz^8*9x^6y^0z^2 = 15x^7z^{10}$

Step-by-step explanation:

Given

$\frac{5}{3}xz^a*bx^cy^dz^2 = 15x^7z^{10}$

Simplify

$\frac{5}{3}b*x^{1+c}z^{a+2}y^d = 15x^7z^{10}y^0$

Compare left and right sides and

Find b:

$\frac{5}{3}$ b = 15 ⇒ b = 15*3/5 = 9

Find c:

1 + c = 7 ⇒ c = 7 - 1 = 6

Find a:

a + 2 = 10 ⇒ a = 10 - 2 = 8

Find d:

d = 0

Solution is:

$\frac{5}{3}xz^8*9x^6y^0z^2 = 15x^7z^{10}$

8 0

3 years ago

If the lowest used price is $3.84 and the average used price is $9.84, What is the price half way between the 2 prices?

TiliK225 [7]

Answer:

$6.84

Step-by-step explanation:

Add the 2 values together and divide by 2

$3.84 + $9.84 = $13.68

$13.68/2 = $6.84

7 0

3 years ago

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Solve the following quadratics. State the FACTORS AND SOLUTIONS. 1. 2x^2 - 7x + 3 2. 3x^2 + 7x +2

tekilochka [14]

Answer:

1. x = 3, 1/2 (solutions); (x - 3)(2x - 1) (factors)

2. x = -1/3, -2 (solutions); (3x + 1)(x + 2) (factors)

Step-by-step explanation:

1. 2x^2 - 7x + 3

To solve problem 1, you will need to identify your a, b, and c values in this quadratic function.

Since this problem is in standard form, it will be easy to identify these values. The standard form of a quadratic function is ax^2 + bx + c.

The a value is 2, the b value is -7, and the c value is 3 if we use our standard form and see which numbers are plugged into it.

Since we know that

a = 2
b = -7
c = 3

we can use the quadratic formula: $x = \frac{-b~\pm~\sqrt{b^2~-~4ac} }{2a}$

Substitute the a, b, and c values into the quadratic formula: $x=\frac{-(-7)\pm\sqrt{(-7)^2-4(2)(3)} }{2(2)}$

Now simplify using the laws of pemdas: $x=\frac{7\pm\sqrt{(49)-(24)} }{4}$

Simplify even further: $x=\frac{7\pm\sqrt{(25)} }{4} \rightarrow x=\frac{7\pm (5) }{4}$

Now split this equation into two equations to solve for x: $x=\frac{12 }{4} ~~and~~ x=\frac{2 }{4}$

12/4 can be simplified to 3, and 2/4 can be simplified to 1/2.

This means your solutions to problem 1 is 3, 1/2.

$\boxed {x=3,\frac{1}{2} }$

There is also another way to solve for the quadratic functions, and this was by factoring.

If you factor 2x^2 - 7x + 3 using the bottoms-up method, you will get (x - 3)(2x - 1).

After factoring, solving for the solutions is simple because all you have to do is set each factor to 0.

x - 3 = 0
2x - 1 = 0

After solving for x by adding 3 to both sides, or by adding 1 to both sides then dividing by 2, you will end up with the same solutions: x = 3 and x = 1/2.

2. 3x^2 + 7x + 2

To save time I'll be using the bottoms-up factoring method, but remember to refer back to problem 1 (quadratic formula) if you prefer that method.

Factor this quadratic function using the bottoms-up method. After factoring you will have (3x + 1)(x + 2). These are your factors.

Now to solve for x and find the solutions of the quadratic function, you will set both factors equal to 0.

3x + 1 = 0
x + 2 = 0

Solve.

First factor: 3x + 1 = 0

Subtract 1 from both sides.

3x = -1

Divide both sides by 3.

x = -1/3

Second factor: x + 2 = 0

Subtract 2 from both sides.

x = -2

Your solutions are x = -1/3 and x = -2.

$\boxed {x = -\frac{1}{3} , -2}$

7 0

3 years ago