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3 years ago

A cafeteria can feed 1/8 of the school in 3 1/2 minutes. How long does it take to feed the school?

Mathematics

2 answers:

goldfiish [28.3K]3 years ago

7 0

The answer is 28 minutes :)

77julia77 [94]3 years ago

6 0

Answer:

28 minutes

3.5 x 8 = 28

Step-by-step explanation:

Feeding the whole school (8/8) would take 8 times as long as feeding 1/8 of the school.

3 1/2 can become 3.5 if that's easier for you to work with.

Feeding 1/8 of the school is 3.5 x 1 = 3.5

Feeding 2/8 of the school is 3.5 x 2 = 7

Feeding 8/8 of the school is 3.5 x 8 = 28

It takes 28 minutes to feed the whole school (8/8)

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A lamina with constant density rho(x, y) = rho occupies the given region. Find the moments of inertia Ix and Iy and the radii of

jenyasd209 [6]

Answer:

Ix = Iy = $\frac{ρπR^{4} }{16}$

Radius of gyration x = y = $\frac{R}{4}$

Step-by-step explanation:

Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.

Mass of disk = ρπR2

Moment of inertia about its perpendicular axis is $\frac{MR^{2} }{2}$ . Moment of inertia of quarter disk about its perpendicular is $\frac{MR^{2} }{8}$ .

Now using perpendicular axis theorem, Ix = Iy = $\frac{MR^{2} }{16}$ = $\frac{ρπR^{4} }{16}$ .

For Radius of gyration K, equate MK2 = MR2/16, K= R/4.

3 0

3 years ago

-3(3+x)+4(x-6)=-4 Please help me with this question

dsp73

Answer:

$\boxed{ \bold{ \huge{ \sf{x = 29}}}}$

Step-by-step explanation:

$\sf{ - 3(3 + x) + 4(x - 6) = - 4 }$

Distribute -3 through the parentheses

Similarly, Distribute 4 through the parentheses

⇒ $\sf{ - 9 - 3x + 4x - 24 = - 4}$

Collect like terms

⇒ $\sf{x - 9 - 24 = - 4}$

Calculate

⇒ $\sf{x - 33 = - 4}$

Move 33 to right hand side and change it's sign

⇒ $\sf{x = - 4 + 33}$

Calculate

⇒ $\sf{x = 29}$

Hope I helped!

Best regards!!

7 0

3 years ago

What is the answer to -5(-3w-8)=21 for w

Sauron [17]

Answer:

w = -1.266

Step-by-step explanation:

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3 years ago

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Nikolay [14]

52s + 30b because 52 x s + 30 x b = 52s + 30b

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3 years ago

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postnew [5]

For this case we have:

Let a function of the form $y = f (x)$

By definition, to graph $y = f (x + h)$ , where $h> 0$ , we must move the graph of f (x), h units to the left.

We observe that the red graph has the same form as the black graph, but it is displaced "h" units to the left.

It is observed that $h = 3$

So, if the black graph is given by $y = f (x)$ , the red graph is given by: $y = f (x + 3)$

Answer:

$y = f (x + 3)$

Option A

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3 years ago

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