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irga5000 [103]
1 year ago
7

Help pleaseeeeeeeeeee

Mathematics
1 answer:
vazorg [7]1 year ago
3 0

Answer:

see below

Step-by-step explanation:

  y = x^2 - 6x + 14        'complete the square for 'x'  

       x^2 - 6x + 9    - 9   + 14

 y =  (x-3)^2 + 5           vertex from     <u> vertex = (3,5) </u>

                            since the coefficient of ^2 is positive it is a bowl shaped parabola and the vertex is a <u>MINUMUM</u>

    vertex  

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jan spent 45 for two shirts and 60 for a pair of jeans. she has 7 left over. how much money did jan take shopping
Evgen [1.6K]
I hope this is in dollars. Remember to always put a label on a number. Who knows, maybe this person paid in bananas.
$45+$60+$7= $112.
8 0
2 years ago
Type the correct answer in each box. A circle is centered at the point (5, -4) and passes through the point (-3, 2). The equatio
Galina-37 [17]

Answer:

(x+ \boxed{-5})^2+(y+\boxed4)^2=\boxed{100}

Step-by-step explanation:

Given:

Center of circle is at (5, -4).

A point on the circle is (x_1,y_1)=(-3, 2)

Equation of a circle with center (h,k) and radius 'r' is given as:

(x-h)^2+(y-k)^2=r^2

Here, (h,k)=(5,-4)

Radius of a circle is equal to the distance of point on the circle from the center of the circle and is given using the distance formula for square of the distance as:

r^2=(h-x_1)^2+(k-y_1)^2

Using distance formula for the points (5, -4) and (-3, 2), we get

r^2=(5-(-3))^2+(-4-2)^2\\r^2=(5+3)^2+(-6)^2\\r^2=8^2+6^2\\r^2=64+36=100

Therefore, the equation of the circle is:

(x-5)^2+(y-(-4))^2=100\\(x-5)^2+(y+4)^2=100

Now, rewriting it in the form asked in the question, we get

(x+ \boxed{-5})^2+(y+\boxed4)^2=\boxed{100}

4 0
3 years ago
What values of k will make the line containing points (k,3) and (-2,1) parallel to the line through (5, K) and (1,0)
rjkz [21]

Answer:

k = -4 or 2

Step-by-step explanation:

For the lines to be parallel, the lines would need to be the same slope. This means to find the slope of each we would take the difference of the rise over the run.

\frac{1-3}{-2-k}=\frac{-2}{-2-k}

and

\frac{0-k}{1-5}=\frac{-k}{-4}

To find K, set them equal.

\frac{-2}{-2-k} = \frac{-k}{-4}\\-k(-2-k) = -2*-4\\2k+k^2=8\\k^2+2k-8=0

Factor the quadratic and solve for K.

(k+4)(k-2)=0

k+4=0 so k=-4

k-2=0 so k=2

4 0
3 years ago
(b^2)^o=b^8 <br> a 6<br> b 4<br> c 3<br> d 1/16
jenyasd209 [6]

Answer:

(b^2)^o=b^8

a 6

b 4

the answer is A.6

5 0
3 years ago
I only need number 1 i don’t understand.
valentinak56 [21]

Answer:

12

Step-by-step explanation:

in this problem there is A+b=15

A=9

B=12

5 0
3 years ago
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