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3 years ago

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Rebecca's father is 2 times as old as Rebecca. The sum of their ages is no less then 69. Find an inequality that can be used to

represent the situation.
A) x+2x>69
B) x+2x<69
C) x+2x≤69
D) x+2x≥69

1 answer:

ivanzaharov [21]3 years ago

4 0

D) x+2x≥69
Rebecca's age plus her father's (Rebecca's times two) must be equal to or more than 69.

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5 1/6 divided by 2 5/12= 2 4/29 true or false

Alex_Xolod [135]

5 1/6 divided by 2 5/12 is 2 4/29 so it is true

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3 years ago

On a certain hot summer's day, 581 people used the public swimming pool. The daily prices are $1.50 for children and $2.50 for

Tanya [424]

Answer:

A = 219

C = 362

Step-by-step explanation:

Given,

581 = C + A

and

$1090.50 = 1.5C + 2.5A

solve 1st for A

A =581 - C

substute into 2nd

1090.50 = 1.5C + 2.5(581 - C)

solve for C

1090.50 = 1.5C + 1452.50 - 2.5C

1090.50 = -C + 1452.50

1090.50 - 1452.50 = -C

-362 = -C

C = 362

then

581 = C + A

581 = 362 + A

219 = A

A = 219

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2 years ago

Create a rule to find the nth term. <br> 4096, 2048, 1024, ...

ella [17]

Answer:

n=4096+(n-1)*-2048

Step-by-step explanation:

8 0

2 years ago

HEEELР ПОЖАЛУЙСТА HELР

seropon [69]

So for question one (about the equilateral triangle), you know any triangle equals 180 degrees. So an equilateral triangle has all equal angles, so 180/3 would equal 60 degrees for each angle.

Now for the first triangle out of the three isosceles.

You should know that there are two equal sides and one side that is not equal in a isosceles triangle.

So if one side is 34 degrees, and the other two are equal, then you first subtract 34 degrees from 180 degrees, because again, all triangles have 180 degrees. So 180-34 would equal to 146 degrees left. Now you divide 146 by two, because the other two angles are equal to each other. So 146/2 = 73 degrees for each of the remaining angles.

For the second triangle out of the three isosceles.

First, let's just calculate half of the triangle first. You already know two angles, 30 and 90 degrees (hence the 90 degree symbol).

So 30 + 90 would equal 120 degrees in total out of 180 degrees (because 1 triangle = 180 degrees).

So if you subtract 180-120 or 120 + ? = 180 to know the remaining angle of the half of the triangle, you would get 60 degrees left. And that also goes with the other side of the top angle of the entire triangle, so your answer for the second one would be 60 degrees. :-)

For the third triangle out of the three isosceles.

You know one angle is 75 degrees.

If you turn your screen a little bit (like about 90 degrees) to the left, you would see that two sides (with the x degree in the middle) is equal. So then know you know the other side of the triangle would also be 75 degrees, because one side that is equal has 75 degrees.

Now you have two 75 degrees, you add 75 + 75, which gives you 150 degrees now.

So obviously again, 180 degrees is the total amount of degrees in a triangle, and you want to know the last degree that would make the triangle equal to 180 degrees out of 150 degrees, so 180-150 or 150 + ? = 180, which gives you 30 degrees for x for the third isosceles triangle.

try doing the fourth one by yourself lol

5 0

3 years ago

Solve the following System of Three Equations:<br> x−3y+z=−15<br> 2x+y−z=−2<br> x+y+2z=1

SashulF [63]

Answer:

x = -3 , y = 4 , z = 0

Step-by-step explanation:

Solve the following system:

{x - 3 y + z = -15

2 x + y - z = -2

x + y + 2 z = 1

Hint: | Choose an equation and a variable to solve for.

In the first equation, look to solve for z:

{x - 3 y + z = -15

2 x + y - z = -2

x + y + 2 z = 1

Hint: | Solve for z.

Subtract x - 3 y from both sides:

{z = 3 y + (-x - 15)

2 x + y - z = -2

x + y + 2 z = 1

Hint: | Perform a substitution.

Substitute z = -15 - x + 3 y into the second and third equations:

{z = -15 - x + 3 y

15 + 3 x - 2 y = -2

x + y + 2 (-15 - x + 3 y) = 1

Hint: | Expand the left hand side of the equation x + y + 2 (-15 - x + 3 y) = 1.

x + y + 2 (-15 - x + 3 y) = x + y + (-30 - 2 x + 6 y) = -30 - x + 7 y:

{z = -15 - x + 3 y

15 + 3 x - 2 y = -2

-30 - x + 7 y = 1

Hint: | Choose an equation and a variable to solve for.

In the second equation, look to solve for x:

{z = -15 - x + 3 y

15 + 3 x - 2 y = -2

-30 - x + 7 y = 1

Hint: | Isolate terms with x to the left hand side.

Subtract 15 - 2 y from both sides:

{z = -15 - x + 3 y

3 x = 2 y - 17

-30 - x + 7 y = 1

Hint: | Solve for x.

Divide both sides by 3:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

-30 - x + 7 y = 1

Hint: | Perform a substitution.

Substitute x = (2 y)/3 - 17/3 into the third equation:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

(19 y)/3 - 73/3 = 1

Hint: | Choose an equation and a variable to solve for.

In the third equation, look to solve for y:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

(19 y)/3 - 73/3 = 1

Hint: | Isolate terms with y to the left hand side.

Add 73/3 to both sides:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

(19 y)/3 = 76/3

Hint: | Solve for y.

Multiply both sides by 3/19:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

y = 4

Hint: | Perform a back substitution.

Substitute y = 4 into the first and second equations:

{z = -x - 3

x = -3

y = 4

Hint: | Perform a back substitution.

Substitute x = -3 into the first equation:

{z = 0

x = -3

y = 4

Hint: | Sort results.

Collect results in alphabetical order:

Answer: {x = -3 , y = 4 , z = 0

4 0

3 years ago