<span>A-2b=2
A-b=6
</span>
<span>A-2b=2
-2(A-b=6)
-2A+2b= -12
A-2b=2
-2A+2b = -12
-------------------
-A = -10
-A/-1 = -10/-1
A = 10
a-b=6
10 - b = 6
10-10-b = 6 -10
-b = -4
-b/-1 = 14/-1
b= 4
Check
a - 2b =2
10 - 2(4) =2
10 - 8 = 2
2=2
</span>
Answer: Applicants with advanced skilled and education.
Step-by-step explanation:
I just took a test.
Solution
The table below is the required sample space of the to fair die
From the above table
The sample space contain 36 outcomes
Event A: The sum is greater than 9
we will look at the table and count all the elements that are greater than 9
There are 6 elements (they are 10, 10, 10, 11, 11, 12 from the table)
The probability for event A will be

P(A) = 1/6
Event B: The sum is an even number.
We will look at the table and count the number of elements that are even
There are 18 elements (notice that there are 3 even number on each of the 6 rows of the table)
The probability for event B will be

p(B) = 1/2
It depends on what the level of significance (alpha) is.
Since alpha is not stated, I'll assume that alpha = 0.05 by default.
Because the p-value is smaller than alpha, we reject the null hypothesis.
Therefore, we conclude that the alternative hypothesis is correct and the proportion of heads is greater than 0.5