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Nadya [2.5K]
3 years ago
5

PLEASE HELP

Mathematics
1 answer:
34kurt3 years ago
5 0
I believe that in this problem, we are asked for the hypotenuse of the triangle that can be formed when we make a right triangle out of the planes and the intersection of their paths. To solve for the hypotenuse of a right triangle, we make use of the equation,
                                   h² = 64.2² + 85.7²
The value of h from the equation is equal to 106.0 miles. 
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Please answer this question now
almond37 [142]

Answer:

98.1km²

Step-by-step explanation:

The name of the Triangle in this question is: WXV

In the question, we have:

Angle W = ? Unknown

Angle X = 119°

Angle V = 34°

Side w =?

Side x = 26km

Side v = ?

Step 1

We have to find the missing third angle = Angle W

Sum of angles in a triangle = 180°

= Angle W = 180° - (119 + 34)°

= 180° - 153°

Angle W = 27°

Step 2

Find the sides w and v using the sine rule

Sine rule =

a/ sin A = b/ Sin B

Hence for triangle WXV

w/ sin W = x/ sin X = v/ sin V

We have the following values

Angle W = 27°

Angle X = 119°

Angle V = 34°

We are given side x = 26km

a) Finding side w

w/ sin W= x/ sin X

w/sin 27 = 26/sin 119

Cross Multiply

sin 27 × 26 = w × sin 119

w = sin 27 × 26/sin 119

w = 13.49587km

w = 13.5km

b) Finding side v

x / sin X= v/ sin V

26/ sin 119 = v/sin 34

Cross Multiply

sin 119 × v = 26 × sin 34

v = sin 34 × 26/sin 119

v = 16.62324km

v = 16.62km

Step 3

Detemine the area of triangle WXV

We make use heron formula

= √s(s - w) (s - x) (s - v)

Where s = w + x + v/ 2

s = (13.5 + 26 + 16.62)/2

s = 56.12/2

s = 28.06

Area of the triangle = √28.06× (28.06 - 13.5) × (28.06 - 26 ) × (28.06 - 16.62)

Area of the triangle = √9628.137559

Area of the triangle = 98.123073530337km²

Approximately to the nearest tenth =98.1km²

7 0
3 years ago
If you prove that △ABD is congruent to △CDB, which general statement best describes what you have proved?
fredd [130]

Answer:

  A: Opposite sides of a parallelogram are congruent

Step-by-step explanation:

The only diagonal involved is BD, so none of the statements regrading diagonals has been proven. The only thing proven is ...

  AB ≅ CD . . . . opposite sides are congruent

  AD ≅ CB . . . . opposite sides are congruent

5 0
2 years ago
In a quadrilateral, consecutive angles and opposite angles are congruent. What is the most specific name of the figure?
ratelena [41]
The four angles are congruet. So each angle is 90°.

So the figure is a rectangle. It could be a square but not necessarily. You can consider a square a special case of rectangle.

The four angles of a rectangle are congruent. And the opposite sides are congruent.

The four angles of a square are congruent. The opposite sides are congruent, furthermore the four sides are congruent.
5 0
3 years ago
The function f(x) = –x2 – 4x + 5 is shown on the graph. Which statement about the function is true? The domain of the function i
Viefleur [7K]

we have

f(x) = -x^{2} - 4x + 5

using a graph tool

see the attached figure

the domain of the function is all real numbers------> the interval is (-∞,∞)

the range of the function is --------------------------------> the interval (-∞,9]

therefore

the answer is

The range of the function is all real numbers less than or equal to 9

7 0
3 years ago
Read 2 more answers
Determine the radius and center of the circle with the following equation <br> x^2+y^2-12x+24y-10=6
PolarNik [594]

Answer:

Center: (6, -12)

Radius: 4

Step-by-step explanation:

<u>Complete the squares</u>

<u />x^2+y^2-12x+24y-10=6\\\\x^2-12x-10+y^2+24y=6\\\\x^2-12x-10+46+y^2+24y+144=6+46+144\\\\(x^2-12x+36)+(y^2+24y+144)=196\\\\(x-6)^2+(y+12)^2=196

Comparing with the standard form equation (x-h)^2+(y-k)^2=r^2, since r^2=196, then the radius of the circle is r=14. Also, the center of the circle would be (h,k)\rightarrow(6,-12).

8 0
2 years ago
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