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crimeas [40]
3 years ago
14

Do consumers spend more on a trip to Store A or Store​ B? Suppose researchers interested in this question collected a systematic

sample for 85 Store A customers and 82 Store B customers by asking customers for their purchase amount as they left the store. Using the given summary​ statistics, researchers calculated a​ 95% confidence interval for the mean difference between Store A and Store B purchase amounts. The interval was ​($negative 15.96​,$negative 4.04​). Explain in context what this interval means.
Mathematics
1 answer:
FinnZ [79.3K]3 years ago
4 0

Answer:

We can be 95% confident that consumers spend between $4.04 and $15.96 less at Store A than the consumers spend at Store B.

Step-by-step explanation:

Confidence Intervals give an estimate as range of values for a statistic concerned at a <em>confidence level</em>.

In this case the statistic is the mean difference between Store A and Store B purchase amounts and the confidence level is 95%.

Confidence Interval can be calculated using M±ME where

  • M is the sample mean difference between Store A and Store B purchase amounts
  • ME is the margin of error from the mean
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Step-by-step explanation:

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A company produces three different types of wrenches: W111, W222, and W333. It has a firm order for 2,000 W111 wrenches, 3,750 W
lawyer [7]

Answer:

z (min) =  150090.8    ( monetary units )  ( $ )

x₁  =  2000     x₄  = 0     x₂  =  3382   x₅  =  368   x₃ = 0  x₆ = 1700

Step-by-step explanation:

wrenches produced in-house   ( W111 = x₁   W222 = x₂  W333 = x₃ )

x₁      x₂    and  x₃

wrenches produced outside  (W111 = x₄  W222 = x₅  W333 = x₆ )

x₄     x₅    and  x₆

Objective function:

z  =  17*x₁  +  20.40*x₄  +  19*x₂  + 21.85*x₅ + 23*x₃ + 25.76*x₆   to minimize

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2.5*x₁  +  3.4*x₂  +  3.8*x₃   ≤  16500

Second constraint: Inspection hours : 1600

0.25*x₁  +  0.3*x₂  +  0.45*x₃  ≤ 1600

Three demands constraint:

x₁    +   x₄   =  2000

x₂   +  x₅    =  3750

x₃   + x₆     =  1700

x₁  ≥  0     x₂  ≥   0     x₃  ≥  0   x₄  ≥  0   x₅  ≥  0   x₆  ≥  0    all integers

After 6 iterations with on-line solver the solution is:

z (min) =  150090.8    ( monetary units )  ( $ )

x₁  =  2000     x₄  = 0     x₂  =  3382   x₅  =  368   x₃ = 0  x₆ = 1700

6 0
3 years ago
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blagie [28]

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\dfrac{2020^3-1}{2021^3+1} = \dfrac{2020-1}{2020+2} = \dfrac{2019}{2022}=\dfrac{673}{674}=\dfrac ab

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snow_tiger [21]

Given:

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