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3 years ago

Is (6,-10) a solution of y=3x-8

1 answer:

6 0

You can easily test this if you know that (6, -10) corresponds to (X, Y). Knowing this, you can:

X = 6
Y = -10

you put this into your equation:

-10 = 3*6 - 8

calculate it:

-10 = 18 - 8
-10 = 10
This is not true of course, -10 is not equal to 10. Therefore, (6, -10) is not a solution of y = 3x-8 :)

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What is the answer?!!!

Alika [10]

The answer is D. Because 5 more change means that his lunch has to cost $14 or less

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3 years ago

After being rejected for employment, Kim Kelly learns that the Bellevue Credit Company has hired only three women among the last

mixer [17]

Answer:

0.00071 = 0.71% probability of getting three or fewer women when 21 people are hired. This probability, which is very small, supports the charge of gender discrimination.

Step-by-step explanation:

For each employee hired, the are only two possible outcomes. Either it is a man, or it is a woman. The probability of a person hired being a man or a woman is independent of any other person. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

21 new employees.

This means that $n = 21$

She also learns that the pool of applicants is very large, with an approximately equal number of qualified men as qualified women.

This means that $p = 0.5$

Help her address the charge of gender discrimination by finding the probability of getting three or fewer women when 21 people are hired.

This is

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{21,0}.(0.5)^{0}.(0.5)^{21} \approx 0$

$P(X = 1) = C_{21,1}.(0.5)^{1}.(0.5)^{20} = 0.00001$

$P(X = 2) = C_{21,2}.(0.5)^{2}.(0.5)^{19} = 0.0001$

$P(X = 3) = C_{21,3}.(0.5)^{3}.(0.5)^{18} = 0.0006$

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0 + 0.00001 + 0.0001 + 0.0006 = 0.00071$

0.00071 = 0.71% probability of getting three or fewer women when 21 people are hired. This probability, which is very small, supports the charge of gender discrimination.

8 0

3 years ago

Which of the following equations have infinitely many solutions? Choose all answers that apply: A 6x + 35 = –60 – 35 -6x + 35 =

frozen [14]

Answer:

The answer is C because they have the same coefficient and variable on both sides (or something like that but its definitely c )

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2 years ago

Which input is incorrect

Sladkaya [172]

The answer you are looking for is A. 7.00. The cost of the item should be $6.00 as the tax should be $0.48. Making the total cost of the item $6.48.

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