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Triss [41]
2 years ago
13

Design an instructional activity that could help learners recognise that decimal

Mathematics
1 answer:
sp2606 [1]2 years ago
8 0

Fraction refers to a part of a whole; e.g when cup is not completely filled, it covers only a part of the cup

<h3>What is fraction?</h3>

The term fraction refers to a part of a whole. To design an instructional activity that  could help learners recognize that decimal fractions can be applied across environmental situations, we could look at certain things in the house.

For instance, when cup is not completely filled, it contains water that covers only an fraction of the cup. Also, we could boil a part and not a whole cup of rice. These are all examples of fractions.

Learn more about fractions:brainly.com/question/10354322

#SPJ1

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Answer:

P(-2 \leq \bar X -\mu \leq 2)

If we divide both sides by \frac{\sigma}{\sqrt{n}} we got:

P(\frac{-2}{\frac{4}{\sqrt{9}}}\leq Z \leq \frac{2}{\frac{4}{\sqrt{9}}})

And we can use the normal distribution table or excel to find the probabilites and we got:

P(-1.5 \leq Z \leq 1.5)= P(ZStep-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the area of a population, and for this case we know the distribution for X is given by:

X \sim N(M,4)  

Where \mu=M and \sigma=4

We select a a sample of n =4 and since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we want to find this probability:

P(-2 \leq \bar X -\mu \leq 2)

If we divide both sides by \frac{\sigma}{\sqrt{n}} we got:

P(\frac{-2}{\frac{4}{\sqrt{9}}}\leq Z \leq \frac{2}{\frac{4}{\sqrt{9}}})

And we can use the normal distribution table or excel to find the probabilites and we got:

P(-1.5 \leq Z \leq 1.5)= P(Z

8 0
3 years ago
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