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blagie [28]
1 year ago
11

3z^2-4z+11 -(12z^2+2z-11 find the difference . polynomials functions

Mathematics
1 answer:
Brrunno [24]1 year ago
6 0

Answer:

−135z

2

−2z
The 2 is representing Square

Step-by-step explanation:

(3z)
2

−4z+11−(12z)
2

+2z−11

Expand (3z)

2

.

3

2

z

2

−4z+11−(12z)

2

+2z−11

Calculate 3 to the power of 2 and get 9.

9z

2

−4z+11−(12z)

2

+2z−11

Expand (12z)

2

.

9z

2

−4z+11−12

2

z

2

+2z−11

Calculate 12 to the power of 2 and get 144.

9z

2

−4z+11−144z

2

+2z−11

Combine 9z

2

 and −144z

2

 to get −135z

2

.

−135z

2

−4z+11+2z−11

Combine −4z and 2z to get −2z.

−135z

2

−2z+11−11

Subtract 11 from 11 to get 0.

−135z

2

−2z

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Answer:

(-5  , 2 )

Step-by-step explanation:

hello :

×-5y=-15

5y = x+15

y = (1/5)x+3    for x= - 5    y = (1/5)(-5) +3  so :  y = 2

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3 years ago
A number, y, is five times another number, x. The sum of the two numbers is 42. Write the system of equations.
vovikov84 [41]

Answer:

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Step-by-step explanation:

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2 years ago
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1 year ago
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Using the mean concept, it is found that:

Relative to Sabrina's goal, her average swim time over the last five weeks is 0.1 hours.

-----------------------

The mean of a data-set is given by the <u>sum of all observations divided by the number of observations</u>.

In this problem:

  • The data-set is her swim time relative to her goal, which is: {1.25, -1, 2.25, 0, -2.}
  • 5 observations.

Thus, the mean is:

M = \frac{1.25 - 1 + 2.25 + 0 - 2}{5} = 0.1

Relative to Sabrina's goal, her average swim time over the last five weeks is 0.1 hours.

A similar problem is given at brainly.com/question/24787716

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