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crimeas [40]
3 years ago
8

3. If the line tangent to the graph of the function f at the point (1,7) also passes through the point

Mathematics
1 answer:
Usimov [2.4K]3 years ago
5 0

Answer:

f'(-1)= 3

Step-by-step explanation:

slope = (y2 - y1)/(x2 - x1)= (7-(-2))/(1-(-2))=9/3=3

Slope of the tangent line in the given point equals f' at this point.

So,

f'(-1)= 3

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(6k^4-k^3-8k)-(5k^4+6k-8k^3)​
DerKrebs [107]

Answer:

9y⁴−9y

Step-by-step explanation:

Subtract 8y48y4 from 5y45y4.

6y4−y−8y−(−3y4)6y4-y-8y-(-3y4)

Multiply −3-3 by −1-1.

6y4−y−8y+3y46y4-y-8y+3y4

Simplify by adding terms.

Add 6y46y4 and 3y43y4.

9y4−y−8y9y4-y-8y

Subtract 8y8y from −y-y.

9y⁴−9y

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3 years ago
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Answer:

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4 0
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Vlad1618 [11]

Answer:

-40

Step-by-step explanation:

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Step-by-step explanation:

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-4(2x + 4) > 8x + 64
romanna [79]

Hello there I hope you are having a great day :)

Your Question, -4(2x + 4) > 8x + 64 Solve for X

1) Expand -8x-16>8x+64

2) Add 16 to both sides -8x-16+16>8x+64+16

3) Simplify -8x>8x+80

4) Subtract 8x from both sides -8x-8x>8x+80-8x

5) Simplify -16x>80

6) Multiply both sides -1 (Reverse the inequality) (-16x) (-1) >80 (-1)

7) Simplify 16x<-80

8) divide both sides by 16   16x/16 <  -80/16

9) Simplify x < -5  

This should be your answer x < -5

Hopefully that helps you :)

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2 years ago
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